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vlada-n [284]
3 years ago
7

1. Reduce the following expression to a single function of one angle: cos(45° + A) + cos(45° − A).

Mathematics
1 answer:
Virty [35]3 years ago
6 0

Hope this helps you!!!!!

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Question 1. How many planes are shown in he figure
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B,c,c,a those are the answers :))
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Edgar is scuba diving 50 feet below the water. He is swimming to the surface at a rate of 3 feet per second. Write an equation t
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i know the answer but not the equation

Step-by-step explanation:

6 0
3 years ago
Find the measures of the four numbered angles
aev [14]
1. 34.5
2. 111
3. 69
4. 34.5 

(mind you I took geometry a year ago and hated it but hopefully these are right?)
6 0
3 years ago
1) ACT Prep: Linear Pair angles have measures (6x -9)°and (9x-6)° 1.
iris [78.8K]

The measure of angles are 69 degree and 111 degree

<em><u>Solution:</u></em>

Given is linear pair angles

The measure of angles are: (6x - 9) degrees and (9x - 6) degrees

A linear pair of angles is formed when two lines intersect.

The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

Therefore,

(6x - 9) + (9x - 6) = 180\\\\\text{Remove the parenthesis and solve}\\\\6x - 9 + 9x - 6 = 180\\\\\text{Combine the like terms}\\\\6x + 9x - 15 = 180\\\\15x - 15 = 180\\\\\text{Move the constants to right side}\\\\15x = 180 + 15\\\\15x = 195\\\\x = 13

<em><u>Thus the measure of angles are:</u></em>

(6x - 9) \text{ degrees } = 6(13) - 9 = 78-9 = 69 \text{ degrees }\\\\(9x - 6) \text{ degrees } = 9(13) - 6 = 117 - 6 = 111 \text{ degrees }

Thus measure of angles are 69 degree and 111 degree

5 0
3 years ago
What is the area of the shaded region on the graph shown?
Sindrei [870]

Answer:

As Doris Day said: Good morning to you

Answer 27/2

Step-by-step explanation:

f(x)=-x^3+5x\\F(x)=-\dfrac{x^4}{4} +\dfrac{5x^2}{2} \\F(2)=\dfrac{-16}{4}+\dfrac{20}{2}  =6\\\\F(-1)=\dfrac{-1}{4} +\frac{5}{2} =\dfrac{9}{4} \\g(x)=\dfrac{3x^2}{2}+\dfrac{x}{2}-5\\\\G(x)=\dfrac{x^3}{2}   +x^2-5x\\\\G(2)=4+1-10=-5\\\\G(-1)=\dfrac{-1}{2} +\dfrac{1}{4} +5=\dfrac{19}{4} \\\\\int\limits^2_{-1} {(f(x)-g(x))} \, dx =F(2)-G(2)-(F(-1)-G(-1))\\\\=11+\dfrac{5}{2} =\dfrac{27}{2}

5 0
3 years ago
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