Answer:
$19.07
Step-by-step explanation:
Look at image above...
Let x be the <span>length of each of two congruent sides.
</span>The triangle will be аcute if:
x² + x² > 8²
2x² > 64
x² > 32
x > √32
x > 5.657
So, the smallest possible length of one of two congruent sides have to be 5.7 cm (<span>to the nearest tenth)</span>
Answer:
b||c; c||d; b||d
Step-by-step explanation:
Substituting 10 for x, in the angle beside b we have
7(10)-5 = 70-5 = 65
In the angle beside c we have
10(10)+15 = 100+15 = 115
In the angle beside d we have
12(10)-5 = 120-5 = 115
In the angle beside we have
8(10)-25 = 80-25 = 55
The angle beside c has a vertical angle on the other side of c. This angle would be same-side interior angles with the angle beside b; this is because they are inside the block of lines made by b and c and on the same side of a, the transversal. These two angles are supplementary; this is because 65+115 = 180. Since these angles are supplementary, this means that b||c.
The angle beside c and the angle beside d would be alternate interior angles; this is because they are inside the block of lines made by c and d and on opposite sides of the transversal. These two angles are congruent; this means that c||d.
Since b||c and c||d, by the transitive property, b||d.
Answer:
f(x)=8-4
Step-by-step explanation:
f(x) = 8 (x+1/4)^2-1/2
f(x) = 8 – (x+1/4)^2-1/16
f(x) = 8 – 2
f(x) = 8 – 4
Answer:
The coordinates of point S are (8,-2)
Step-by-step explanation:
we know that
The formula to calculate the midpoint between two points is equal to
![M=(\frac{x1+x2}{2},\frac{y1+y2}{2})](https://tex.z-dn.net/?f=M%3D%28%5Cfrac%7Bx1%2Bx2%7D%7B2%7D%2C%5Cfrac%7By1%2By2%7D%7B2%7D%29)
Let
Point S(x2,y2)
substitute the given values
![(1,2)=(\frac{-6+x2}{2},\frac{6+y2}{2})](https://tex.z-dn.net/?f=%281%2C2%29%3D%28%5Cfrac%7B-6%2Bx2%7D%7B2%7D%2C%5Cfrac%7B6%2By2%7D%7B2%7D%29)
<em>Solve for x2</em>
![1=(-6+x2)/2\\2=-6+x2\\x2=2+6=8](https://tex.z-dn.net/?f=1%3D%28-6%2Bx2%29%2F2%5C%5C2%3D-6%2Bx2%5C%5Cx2%3D2%2B6%3D8)
<em>Solve for y2</em>
![2=(6+y2)/2\\4=6+y2\\y2=4-6=-2](https://tex.z-dn.net/?f=2%3D%286%2By2%29%2F2%5C%5C4%3D6%2By2%5C%5Cy2%3D4-6%3D-2)
therefore
The coordinates of point S are (8,-2)