Let's call:
M = necklaces owned by Mary Sue
B = necklaces owned by Betty
You know that:
M + B = 603
M - B = 115
Therefore, when you have the sum and the difference of two numbers, in order to find the biggest number you have to sum the sum and the difference and divide it by 2, and in order to find the smallest number you have to subtract the difference from the sum and divide it by 2:
M = [(M + B) + (M - B)] ÷ 2
= [603 + 115] ÷ 2
= 359
B = [(M + B) - (M - B)] ÷ 2
= [603 - 115] <span>÷ 2
= 244
</span>
Hence, Mary Sue has 359 necklaces and Betty has 244 necklaces.
Answer:
C)78.5
Step-by-step explanation:
∠BOZ = X
∠WOB = 7X - 4
X + 7X -4 = 180 {STRAIGHT LINE }
8X = 180 + 4
8X = 184
X = 184/8
X = 23
∠WOB = 7X - 4 = 7*23 - 4 = 161 - 4 = 157
OA bisects ∠WOB. So, ∠WOA =∠AOB
∠AOB = 1/2 of ∠WOB = 157/2 = 78.5
Answer:
= 2345<u>6</u><u>7</u><u>8</u><u>9</u><u>1</u><u>0</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>=</u><u>6</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>midp</u><u>oint</u>
There are two equations you can get from this.
2.5X+1.25Y=1375
X+Y=700
By solving for X, we can then plug the 2nd equation into the first equation.
X=700-Y
2.5(700-Y)+1.25Y=1375
1750-2.5Y+1.25Y=1375
375=1.25Y
Y=300
After we get the Y, we solve for the X.
300+X=700
X=400
There were 400 adults, and 300 children. A quick check proves this.
2.5(400)+1.25(300)=1375
X^2 + 4x - 12
= (x +6)(x - 2)
answer
D. (x +6)(x - 2)