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3 years ago

Which ordered pair is a solution to this equation? 2x + 6y = 10

Mathematics

1 answer:

kobusy [5.1K]3 years ago

5 0

(2,1) because if you plug in 2 for for X you get 4 if you plug in 1 for y you get 6, 4 + 6 is equal to 10

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15 POINTS :) Solve the inequality. -3x+4<25

skad [1K]

Answer:

x > -7

Step-by-step explanation:

-3x + 4 < 25

-3x + 4 - 4 < 25 - 4

-3x < 21

-3x/-3 < 21/-3

x > -7

May i have brainliest? :)

6 0

3 years ago

Read 2 more answers

Choose the set that consists of only prime numbers.

butalik [34]

The answer is C because 2, 5, 23, and 29 are prime numbers (you can also look up a chart and highlighted numbers are prime). prime numbers is a whole number greater than 1 and cannot be formed when multiplying two smaller numbers that are whole. it must involve itself in a multiplication equation.

6 0

3 years ago

Find the derivative using the limit process of f (x) = - 10x

zubka84 [21]

Answer:

$\frac{d}{dx} f(x) =-10$

General Formulas and Concepts:

Calculus

Derivative Notation
Definition of a Derivative: $\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Step-by-step explanation:

Step 1: Define

f(x) = -10x

Step 2: Find Derivative

Substitute: $\frac{d}{dx} f(x)= \lim_{h \to 0} \frac{-10(x + h)-(-10x)}{h}$
Distribute -10: $\frac{d}{dx} f(x)= \lim_{h \to 0} \frac{-10x -10h-(-10x)}{h}$
Distribute -1: $\frac{d}{dx} f(x)= \lim_{h \to 0} \frac{-10x -10h+10x}{h}$
Combine like terms: $\frac{d}{dx} f(x)= \lim_{h \to 0} \frac{-10h}{h}$
Divide: $\frac{d}{dx} f(x)= \lim_{h \to 0} -10$
Evaluate: $\frac{d}{dx} f(x)=-10$

3 0

4 years ago

Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.

Arisa [49]

Answer: $S_n=5(1-\dfrac{1}{n+1})$ ; 5

Step-by-step explanation:

Given series : $[\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]$

Sum of series = $S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]$

Consider $\dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}$

$=\dfrac{1}{n}-\dfrac{1}{n+1}$

⇒ $S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]$

Put values of n= 1,2,3,4,5,.....n

⇒ $S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})$

All terms get cancel but First and last terms left behind.

⇒ $S_n=5(1-\dfrac{1}{n+1})$

Formula for the nth partial sum of the series :

$S_n=5(1-\dfrac{1}{n+1})$

Also, $\lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})$

$=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5$

4 0

3 years ago

Can someone help with with this math question

Alona [7]

The appropriate choice is ...
B. 1/7, 3/4, 5, 7

_____
Only the magnitude of the vertical scale factor affects the apparent width of the graph. The higher its value, the narrower the graph appears to be.

3 0

3 years ago