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Paladinen [302]
4 years ago
11

The area of this circle is 42π m².

Mathematics
2 answers:
son4ous [18]4 years ago
7 0

We will solve this question using the formula for the area of a sector of a circle. We know that the area, A, of a sector of a circle is given by:

A=\frac{\theta}{360^{\circ}}\times \pi r^2

Where \theta is the angle subtended by the sector at the center of the circle. Also, we know that in our case, \theta=60^{\circ}.

Now, we know that \pi r^2 is just the area of the original circle in question here, which has been given to us a 42 \pi.

Thus, the required area of the sector in question here is:

A=\frac{60^{\circ}}{360^{\circ}}\times 42\pi =\frac{1}{6}\times 42 \pi =7 \pi

Thus the area of a 60º sector of this circle is 7 \pi m^2.

Thus, the second option is the correct option.

kondor19780726 [428]4 years ago
4 0
A full circle is 360°, so a 60° circle is 1/6th of the area.

1/6th of 42π m² is 7<span>π m², so answer B.</span>
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