The time that the ball is in the air if the player lets the ball drop is 2.145 sec
What is a quadratic equation?
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax²+ bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
-16t²+32t+5
by comparing this equation to the standard form of the quadratic equation we get
a=-16 b=32 c=5
the time (t) needed for the ball to reach its maximum height using the axis of symmetry formula (x = -b/2a) for a parabola:
the time at which the ball reaches the maximum height using the axis of symmetry formula is (x=-b/2a)
t = -32/2×-16
t=1sec
by putting h(t) to zero and determining the time (t) when the ball hits the ground:
-16t²+32t+5=0
-16(t²+2t+5/16)=0
t²-2t-5/16=0
(t)²-2×1×t+(1)²-5/16=1
(t-1)²=21/16
t-1=√21/√16
t=1+4.58/4
t=1+1.145
t=2.245sec
Learn more about quadratic equations here:
brainly.com/question/1214333
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Answer:
b) 2.45
Step-by-step explanation:
The Euclidean distance in 3-space is the root of the sum of the squares of the x-, y-, and z-differences between the points.
<h3>Application</h3>
For the given points ...
The distance between x and y is ...
Answer:
the -3 is being distributed. --> the 5 stays outside till the end. multiply the 3 inside first, then the negative. and then add the 5 to the final answer
5-3(d+21) = -->> 5-(3d+21)=--->>>5-3d-21=3d-16
Step-by-step explanation:
5-3(d+21) =
5-(3d+21)=
5-3d-21=
ans=3d-16
The answer is 3x^2-19x+1
(-4x+3)-(7x-3x^2-1)
-12x+7x+3x^2+1
Combine like terms:
3x^2+(-12x+-7x)+1
= 3x^2+-19x+1
