2 years ago

What is the equation to find area of a parallelogram

Mathematics

1 answer:

olchik [2.2K]2 years ago

6 0

A=BH

Area = Base x the Hight

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Simplify the expression

miv72 [106K]

6x3= 18 + g =18g (Hope this helped!)

8 0

2 years ago

Need help please asap!

erastovalidia [21]

Answer:

40 degrees

Step-by-step explanation:

90 degrees-50 degrees is equal to 90 degrees.

7 0

2 years ago

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Guys help me pls I need it immediately

julsineya [31]

Answer:

Hey there!

First, we want to find the side length of the large triangle.

1/2bh=y cm^2

bh=2y cm^2

Since b and h are the same here, we have b^2= 2y, $b=\sqrt{2y}$ .

And we have FC= $\frac{\sqrt{2y} }{2}$ .

Area of shaded triangle: $\frac{1}{2} (\frac{\sqrt{2y} }{2})(\frac{\sqrt{2y} }{2})$ .

This is equal to: $\frac{1}{2}(\frac{2y}{4})$ , or y/4.

Let me know if this helps :)

6 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST

egoroff_w [7]

Option 4 is the correct answer

3 0

2 years ago

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¿cual es el perimetro total de un paralelogramo obicuo cuya base mide 2∛54x² cm , y cuyo lado oblicuo mide 3∛54x²?

Step2247 [10]

Answer:

$p=10\sqrt[3]{54}x^2$

Step-by-step explanation:

We are given parallelogram

Since, two opposite sides of any parallelogram are always equal

Let's assume first side =a

second side =b

so, we get

$a=2\sqrt[3]{54}x^2$

$b=3\sqrt[3]{54}x^2$

now, we can find perimeter

perimeter=2a+2b

so, we get

$p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)$

we can simplify it

$p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2$

$p=10\sqrt[3]{54}x^2$ ................Answer

6 0

3 years ago

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