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Oksi-84 [34.3K]
4 years ago
11

How do solve this problem 2/3 (2/8 + 4/8) =

Mathematics
2 answers:
scoundrel [369]4 years ago
6 0

Answer:

1/2

Step-by-step explanation:

2/3 (2/8 + 4/8) =

First simplify what is inside the parentheses

2/8+4/8 = 6/8

Replace with 6/8

2/3 (6/8) =

Then multiply

2*6 =12

3*8 = 24

12/24

Divide top and bottom by 12

1/2

Aneli [31]4 years ago
5 0
In PEMDAS, you do what is in the parentheses first, therefore you solve (2/8 +4/8) first. You would end up with 6/8. Now you multiply 2/3 by 6/8. 2/3*6/8= 1/2 or .5. Hope this helps.
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Answer:

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Step-by-step explanation:

6 0
3 years ago
Find the values of x and y
zhuklara [117]

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


4 0
4 years ago
A triangle has vertices r(1,2), s(3,3) and t(-3,4)
weqwewe [10]

Give The Rest of the question

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I need help with Math ASAP plz!!
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Answer:

x = (74-28)/2

Step-by-step explanation:

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s1 +s2+s3 = P

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We know one of the sides is 28

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Combine like terms

28+2x = 74

We want to solve for x

Subtract 28 from each side

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2x = 74-28

Divide each side by 2

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x = (74-28)/2

4 0
3 years ago
The ratio of 14:1 written
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Ratios can be written 3 ways...

14:1 or 14/1 or 14 to 1
7 0
4 years ago
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