-12/5 divided by -1/5

Determina la masa molar y el volumen que ocupa la siguiente sustancia CO2, si su masa es de 28 gr. *

balandron [24]

Answer:

Para el CO₂ sabemos que:

densidad = 0,001976 g/cm³

Sabemos que:

densidad = masa/volumen

Entonces, si tenemos una masa de 28 g, podemos escribir:

volumen = masa/densidad

volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3

Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.

Carbono: tiene una masa molar de 12 g/mol

Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)

entonces la masa molar va a ser:

masa molar = 12g/mol + 2*16g/mol = 44 g/mol

Es decir, un mol de CO₂, pesa 44 gramos.

7 0

3 years ago

X

Ede4ka [16]

Answer:

Step-by-step explanation:

Sum of all three angle in a triangle=180

Given angles are 35°,45°

Let the remaining angle =x

So 35 +45+X=180

X=180-80

X=100°

Remaining angle =X=100° is the answer

3 0

3 years ago

Given f (g (x)) = x + 4 and f (x) = 3x + 5, find g (x).

JulijaS [17]

Answer:

g(x) = $\frac{1}{3}(x - 1) = \frac{x}{3} - \frac{1}{3}$

Step-by-step explanation:

f(x) = 3x + 5

f[g(x)] = 3[g(x)] + 5

⇒ 3[g(x)] + 5 = x + 4

⇒ 3[g(x)] = x + 4 - 5

⇒ 3[g(x)] = x - 1

⇒ g(x) = $\frac{1}{3}(x - 1) = \frac{x}{3} - \frac{1}{3}$

5 0

2 years ago

The product 33 × 90 is more than 32 × 90. How much more? Complete the explanation for how you know without multiplying.

Tju [1.3M]

Answer:

90, there are 32 ninetys in 32 X 90 and there are 33 ninetys in 33 X 90, meaning there is one more 90 in 33 X 90 than 32 X 90

5 0

3 years ago

The Genetics & IVF Institute conducted a clinical trial of the YSORT method designed to increase the probability of conceivi

Reika [66]

Answer: The test statistic needed to test this claim= 10.92

Step-by-step explanation:

We know that the probability of giving birth to a boy : p= 0.5

i..e The population proportion of giving birth to a boy = 0.5

As per given , we have

Null hypothesis : $H_0: p\leq0.5$

Alternative hypothesis : $H_a: p>0.5$

Since $H_a$ is right-tailed , so the hypothesis test is a right-tailed z-test.

Also, it is given that , the sample size : n= 291

Sample proportion: $\hat{p}=\dfrac{239}{291}\approx0.82$

Test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$ , where n is sample size , $\hat{p}$ is sample proportion and p is the population proportion.

$\Rightarrow\ z=\dfrac{0.82-0.5}{\sqrt{\dfrac{0.5(1-0.5)}{291}}}\approx10.92$

i.e. the test statistic needed to test this claim= 10.92

Critical value ( one-tailed) for 0.01 significance level = $z_{0.01}=2.326$

Decision : Since Test statistic value (10.92)> Critical value (2.326), so we reject the null hypothesis .

[When test statistic value is greater than the critical value , then we reject the null hypothesis.]

Thus , we concluded that we have enough evidence at 0.01 significance level to support the claim that the YSORT method is effective in increasing the likelihood that a baby will be a boy.

7 0

3 years ago