1 3/5 goes between 1 and 2
Answer:
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Step-by-step explanation:
Given that, the rate R(t) at which cars enter the highway is given the formula

The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.

![=[100(t-0.0001\frac{t^3}{3})]_0^{30}](https://tex.z-dn.net/?f=%3D%5B100%28t-0.0001%5Cfrac%7Bt%5E3%7D%7B3%7D%29%5D_0%5E%7B30%7D)
![=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]](https://tex.z-dn.net/?f=%3D100%5B%2830-0.0001%5Cfrac%7B30%5E3%7D%7B3%7D%29-%280-0.0001%5Cfrac%7B0%5E3%7D%7B3%7D%29%5D)
=2901
The average rate of car is 

=97
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Answer:
520 - 303.93 - (10.99 * 4) - 25.25 - 73.43x ≥ 0
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1) Parentheses
520 - 303.93 - 43.96 - 25.25 - 73.43x ≥ 0
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2) Combine like terms
146.86 - 73.43x ≥ 0
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3) Get the variable term alone
-73.43x ≥ -146.86
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4) Divide to solve
x ≤ 2
** dividing by a negative number, the inequality sign flips **
ANSWER :
x ≤ 2
divide the two:
52.50 / 7 = 7.50 per hour