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luda_lava [24]
3 years ago
7

Can some one help me please

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

2x²√13

Step-by-step explanation:

Step 1:  When there is multiplication under a square root sign (also called a radical sign), you can rewrite the expression as the product of two square roots, like this...

√(52x^4)   can be rewritten as     (√52)(√x^4)

Step 2:  x^4 = x²x², so it's the same thing as saying (x²)², or "x-squared, squared".  Taking the square root of it leaves just x-squared, so this simplifies to

  (√52)x²

Step 3:  When taking the square root of a number that is not a perfect square, you need to do a factor tree to see if you can break the number up into a product of perfect squares, or a perfect square multiplied by a prime number.

52 is an even number, so we an at least divide by 2.  

        52/2  is 26, so we have

                  (26)(2)

2 is a prime number, so we don't break that down any further.

26 is even so it is also divisible by 2,

   26/2 is 13, so we have

     (13)(2)(2)

  which we can write as (13)(4)     (groups pairs of numbers together)

(2)(2) is 4, which results in a perfect square, so we can rewrite √52 as

      (√4)(√13),       since √4  = 2, we simplify this expression to

       2√13

So √(52x^4) breaks down to (√52)(√x^4), which further breaks down into

  (2√13)(x²)

We simplify the expression to 2x²√13

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Read 2 more answers
Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

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