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3 years ago

13

A 15 ft pole is leaning against a tree. The bottom of the pole is 9 feet away from the bottom of the tree , Approximately how hi

gh up the tree does the top of the pole reach?

1 answer:

tigry1 [53]3 years ago

8 0

Answer:

12ft

Step-by-step explanation:

you do 15squared×9squared to get 144 then you square root it to make 12

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Question 8 Multiple Choice Worth 1 points)

Anon25 [30]

Answer:

$\dfrac{x}{2}+12=36$

Step-by-step explanation:

As it is given that

Both Riley and Francesca commute to work.

And, the Riley takes 12 minutes more than as Francesca as Riley takes 36 minutes

So for determining how many minutes is required for Francesca to get to work we need

Let us assume the time taken by Francesca to get to work is x

So, the time taken by Riley is

$= \dfrac{x}{2}+12$

And, Riley takes 36 minutes to get to work.

So, the equation would be

$\dfrac{x}{2}+12=36$

5 0

3 years ago

For which values of x is the expression undefined?<br> x2 – 49<br> x2 – 16

Lyrx [107]

You meant to say x^2 - 49 and the second binomial is x^2 - 16.

x^2 - 49 = (x - 7) (x + 7).

Set each factor to 0 and solve for x individually.

x - 7 = 0

x = 7

x + 7 = 0

x = -7

Do the same for x^2 - 16.

Here is the set up:

x^2 - 16 = (x - 4) (x + 4).

Take it from here.

4 0

3 years ago

I need help please?!!!!

Neporo4naja [7]

Answer:

Yes.

Step-by-step explanation:

7 0

3 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

<u />

In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

<u />

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

$X = 6.91$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

The IQR is:

$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

<u />

A similar problem is given at brainly.com/question/15683591

3 0

2 years ago

An artist used a scale factor of 1 in=8 ft to create a model of a building. if the actual building has a height of 64 feet, how

nalin [4]

Answer:

<em>Okay, so what I think you mean to ask what the scale factor between the model and actual building</em> is, so i crunched the numbers. if 1 in equaled 8 feet and the actual thing was 64 ft, then we can just say that 64 divided by 12 is 5.3, so the model could be

5.3 ft. is the size of the model

BUT

you said how many feet are they apart so in inches its 705, in ft its 58.75

Step-by-step explanation:

a foot is 12 in.

64/12 is 5.3

64 ft is 768 inches, and 5.3 is 63.

768-63 = 705.

there are 705 inches in difference, in feet its 58.75

8 0

2 years ago