1) A quadratic will have no real roots when its discriminant is negative


Dividing by 4,

We have a positive coefficient on k^2 so this parabola is a CUP (concave up positive) so has a minimum at the vertex. If the vertex y value is less than zero, the inequality will be true in the range between the zeros.

That's true for

2) We look for the meet of the line and the parabola:


For two intersections we need a positive discriminant:



That's means two negative or two positive, so
or 
CO = AO = 32 (Are rays.)
BO = BC + CO = 98 + 32 = 130
AB ⊥ BO
⇒ ΔAOB is a rectangular triangle.
We use Pitagora's theorem.
Complete question is;
Finding the areas of each of the rectangles and squares of the net of a rectangular prism and adding up those areas gives the surface area or total surface area of the prism. For example, if the length of one side of the cube 4 units then the area of one its face is 4 × 4 = 16 square units. From the net, we can see that there are six equal faces and so we get the total surface area is 6 × 16 = 96 square units.
Find the total surface area of the rectangular prism attached.
Answer:
72 cm²
Step-by-step explanation:
From the rectangular prism attached, we can see that it has 6 sides.
Now, each side has a mirrored part which is of same dimensions with it.
Thus, unfolding to get a net, we have;
2 faces with dimension: 3cm × 6cm
2 faces with dimension: 2cm × 6 cm
2 faces with dimension: 2cm × 3cm
Thus,total surface area is;
2(3cm × 6cm) + 2(2cm × 6cm) + 2(2cm × 3cm) = 36 + 24 + 12 = 72 cm²
Alright so first he paid 45 for the guitar he resold it for 51.75(15% of 45 is 6.75) then spent 18.63(36% is 18.63)on books
I hope this helped...
Answer:
Option a
Step-by-step explanation:
Given two normal distribution samples
I group has 106 as mean and 8.5 as std deviation with sample size = 60
II group has 121 as mean and 6.3 as std deviation with sample size =38
We find mean difference =-15
For margin of error finding, we have to find the combined std error for the difference
Variance of difference = Sum of variances
STd error for difference = 1.50
Hence for 99% margin of error =2.58(1.50)
= 3.87