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fgiga [73]
3 years ago
13

A 15 ft pole is leaning against a tree. The bottom of the pole is 9 feet away from the bottom of the tree , Approximately how hi

gh up the tree does the top of the pole reach?
Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

12ft

Step-by-step explanation:

you do 15squared×9squared to get 144 then you square root it to make 12

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I need help on 1 & 2
Anon25 [30]

Answer:

1 - Avenue A is perpendicular to South St.

2 - 70°

Step-by-step explanation:

1 - North, Center, and South St. are parallel lines. Therefore Ave A will be perpendicular to the three lines.

2 - Ave B and Center street forms a 70° angle. Since Center and South St. are parallel lines, they have corresponding angles. Therefore, Ave B and South St also form a 70° angle. The same is true for Ave B and North St.

3 0
3 years ago
1. tan a = cot(a + 10°)
Temka [501]

Answer:

a=40+90n

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So \tan(a)=\cot(90-a).

We have the equation:

\tan(a)=\cot(a+10)

Make the above replacement:

\cot(90-a)=\cot(a+10)

Since cotangent has period 180 degrees, we can also write this as:

\cot(90-a+180n)=\cot(a+10)

So solving the following will give us a set of solutions for a:

90-a+180n=a+10

Add a on both sides:

90+180n=2a+10

Subtract 10 on both sides:

80+180n=2a

Divide both sides by 2:

40+90n=a

Symmetric property:

a=40+90n

7 0
2 years ago
Divide £300 in a ratio of 3:7
AVprozaik [17]
<span>£</span>210 is the answer!! :)

7 0
2 years ago
Urgent:
rjkz [21]

Step-by-step explanation:

<h3>Given:</h3>
  • CM ⊥ AB
  • ∠3 = ∠4
<h3>To prove: </h3>
  • △AMC ≅ △BMC
<h3>Solution:</h3>
  • ∠ACM≅∠BCM - given

<u>CM⊥AB - given, therefore</u>

  • ∠AMC = 90° and ∠BMC = 90°

<u>Then</u>

  • ∠AMC ≅ ∠BMC
  • Side CM is common, therefore is congruent to itself

<u>So we have congruent two angles and a side between them on triangles AMC and BMC:</u>

  • △AMC ≅ △BMC as per ASA congruency theorem
5 0
2 years ago
Complete the remaining columns in the chart by calculating the missing values for each category. Round your percentages to the n
Alenkinab [10]

Answer:

yearly cost for housing expenses = $11,400, average monthly cost for food = $650

yearly clothing cost = $900,

average monthly cost for transportation= $500,

Yearly cost for insurance & medical= $14,400

yearly cost for emergency fund = $600

average monthly college saving = $50

Step-by-step explanation:

Yearly housing = monthly cost * 12 = 950 * 12 = 11400

Food, monthly = 7800 /12 = 650

Clothing, yearly = 75 * 12 = $900

Monthly transport = 6000 / 12 = $500

Insurance and medical = 1200*12 =14400

Emergency fund = $50 * 12 = $600

College saving = $600 / 12 = $50

8 0
3 years ago
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