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Alisiya [41]
3 years ago
6

Matthew has a 150 page book he has read one third of it how many pages has he read so far

Mathematics
1 answer:
posledela3 years ago
8 0
You take 150/3. The answer is 50.
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If 3 dogs were 2 ft and 4 were 5 what would be the total height of all of them together
seraphim [82]

Answer:

26 i think

Step-by-step explanation:

since the 3 dogs are 2 feet tall you would multiply them then multiply 4 by 5 and get 20 and 3x2 is 6 you add it up and get 26

7 0
3 years ago
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Which of the following sentences corresponds to the generic form of a 2nd degree equation to represent the situation that the tw
mash [69]

Answer:

oioiiji90

Step-by-step explanation:

4 0
3 years ago
Why is it helpful to write numbers in different ways
Goshia [24]
You should write numbers in as many ways as you possibly can to make new connections in your brain. Knowing how to write numbers in many different ways can help you solve complex problems more easily. Doing this can also reinforce the mathematical principles and logic you have memorised.

Writing one in many different ways:

1=1/1=2/2=3/3=4/4=(-1)/(-1)=(-2)/(-2)

=1.0=1.00=1.000=(1/2)+(1/2)=(1/3)+(1/3)+(1/3)

=(1/4)+(1/4)+(1/4)+(1/4)

Writing a half in many different ways:

1/2=(1/4)+(1/4)=(1/6)+(1/6)+(1/6)

=(1/8)+(1/8)+(1/8)+(1/8)=4*(1/8)

=2/4=3/6=4/8=5/10=0.5=0.50

etc...etc...
6 0
3 years ago
In a restaurant, the proportion of people who order coffee with their dinner is p. A simple random sample of 144 patrons of the
mote1985 [20]
<h2>Answer with explanation:</h2>

Given : In a restaurant, the proportion of people who order coffee with their dinner is p.

Sample size : n= 144

x= 120

\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-

Null hypothesis : H_0: p\geq0.85   [ it takes equality (=, ≤, ≥) ]

Alternative hypothesis : H_1: p  [its exactly opposite of null hypothesis]

∵Alternative hypothesis is left tailed, so the test is a left tailed test.

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56

Using z-vale table ,

Critical value for 0.05 significance ( left-tailed test)=-1.645

Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.

Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.

8 0
3 years ago
What is the slope of the equation: x = -2
Harrizon [31]

Answer:

undefined

Step-by-step explanation

it is a vertical line and has no defined slope

5 0
3 years ago
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