Solve for x by finding the missing side of the triangle. Round your answer to the nearest tenth
2 answers:
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First of all, you add 1/3 and 4/5, so you get:
To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
That's the sum of 1/3 + 4/5.
Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15.
Hope this Helps! :D
To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
That's the sum of 1/3 + 4/5.
Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15.
Hope this Helps! :D
Answer:
<em>Test statistic </em>
<em> </em>
t = <em>1.076</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given Mean of the Population (μ) = 8.0
<em>Mean of the sample (x⁻) = 8.25</em>
Given data
8,9,9,8,8,9,8,7
Given sample size n= 8
Given sample standard deviation(S) = 0.661
<u><em>Step(ii):-</em></u>
<em>Null hypothesis : H: (μ) = 8.0</em>
<em>Alternative Hypothesis :H:(μ) > 8.0</em>
<em>Degrees of freedom = n-1 = 8-1=7</em>
<em>Test statistic </em>
<em> </em><em></em>
<em> </em><em></em>
<em> t = 1.076</em>
<em>Critical value </em>
<em> t₍₇,₀.₀₅₎ = 2.3646</em>
<em>The calculated value t = 1.076 < 2.3646 at 0.05 level of significance</em>
<em>Null hypothesis is accepted</em>
<em>Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0</em>
<em></em>