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3 years ago

NEED ASAP. PLEASE HELP ME.

Mathematics

1 answer:

ANTONII [103]3 years ago

4 0

Answer:

metric

Step-by-step explanation:

The system is based off of the decimal system meaning that everything revolves around 10. This makes it much easier to convert in the metric system.

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Juarez scored 32 points in a basketball game. He scored twice as many baskets worth 3 points than baskets worth 2 points. How ma

Vladimir79 [104]

Answer:

8 baskets worth 3 points each and 4 baskets worth 2 points each

Step-by-step explanation:

It is 8 baskets worth 3 points each and 4 baskets worth 2 points each because it says Juarez scored twice as many baskets worth 3 points than the baskets worth 2 points. 4 x 2 = 8

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6 baskets worth 3 points each and 7 baskets worth 2 points each : wrong because 7 x 2 = 14.

10 baskets worth 3 points each and 1 basket worth 2 points : wrong because 1 x 2 = 2.

4 baskets worth 3 points each and 10 baskets worth 2 points each: wrong because 10 x 2 = 40.

8 0

3 years ago

Read 2 more answers

How does the length of the hypotenuse ina right triangle relate to the lengths of the legs?

Simora [160]

I am pretty sure it is "D"

7 0

3 years ago

Which step was the first error made? -3\left(2x-3\right)=33−3(2x−3)=33 -6x+6=33−6x+6=33 step 1 -6x=27−6x=27 step 2 \frac{\left(-

Afina-wow [57]

Given:

The equation is

$-3(2x-3)=33$

The incorrect solution steps are given.

To find:

The first error.

Solution:

We have,

$-3(2x-3)=33$

Using distributive property, we get

$-3(2x)-3(-3)=33$

$-6x+9=33$

The given step 1 is $-6x+6=33$ , which is not correct.

Therefore, there is first error in step 1 because the distribution property is not used properly.

Hence, the correct option is D.

6 0

3 years ago

Simplify completely sqrt of 20Y^8

brilliants [131]

Answer:

Final answer is $2y^4 \sqrt{5}$ .

Step-by-step explanation:

Given expression is $\sqrt{20y^8}$ .

Now we need to smplify the given expression $\sqrt{20y^8}$ .

So begin with factoring 20 into two parts so that one part is perfect square number.

$\sqrt{20y^8}$

$=\sqrt{4 \times 5y^8}$

$=\sqrt{4 y^8} \times \sqrt{5}$

$=2y^4 \times \sqrt{5}$

Hence final answer is $2y^4 \sqrt{5}$ .

3 0

3 years ago

Pwease halp uwu im so dumb...

fgiga [73]

I only made one ,

there I leave you an image with the whole procedure

8 0

4 years ago