Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer:
Step-by-step explanation:
if (x,y)is mid point of two points (x1,y1) ,(x2,y2) then
x=(x1+x2)/2
and y=(y1+y2)/2
coordinates of M are ((-2+(-8))/2,(-7+7)/2)
or are (-5,0)
Answer:
open circle
Step-by-step explanation:
open circle
Answer:
3 or 4 i belive
Step-by-step explanation:
<span> 935.97 = 900 + 30 + 5 + 0.9 + 0.07
hope it helps</span>
