Girl ain’t no way you can’t figure this out? the labeling is easy but like just look up the functions
Answer:
a)
USL = 6.2 inches
LSL = 5.8 inches
b) Cp = 1.33
Cpk = 0.67
c)
Yes it meets all specifications
Step-by-step explanation:
The specification for a plastic handle calls for a length of 6.0 inches ± .2 inches. The standard deviation of the process is estimated to be 0.05 inches. What are the upper and lower specification limits for this product? The process is known to operate at a mean thickness of 6.1 inches. What is the Cp and Cpk for this process? Is this process capable of producing the desired part?
Given that:
Mean (μ) = 6.1 inches, Standard deviation (σ) = 0.05 inches and the length of the plastic handle is 6.0 inches ± .2
a) Since the length of the plastic handle is 6.0 inches ± .2 = (6 - 0.2, 6 + 0.2)
The Upper specification limits (USL) = 6 inches + 0.2 inches = 6.2 inches
The lower specification limits (LSL) = 6 inches - 0.2 inches = 5.8 inches
b) The Cp is given by the formula:

The Cpk is given by the formula:
c)
The upper specification limit lies about 3 standard deviations from the centerline, and the lower specification limit is further away, so practically all units will meet specifications

Answer:
15 percent
Step-by-step explanation:
Answer:
We can solve this question using the slope equation which is y2-y1/x2-x1
If you use that formula and sub in the coordinates
-4 - 5 / -1-2
-9/-3
= 3
The slope should be 3/1
Answer:
<ADB = 61degrees
Step-by-step explanation:
From the diagram shown, triangle ADB is isosceles since they projected out from the chord AD. Hence;
<ABD + <ADB + <BAD = 180
Since <ADB = <BAD, then;
<ABD + <ADB + <ADB = 180
Given that:
<ABD = 58degrees
58 + 2<ADB = 180
2<ADB = 180 - 58
2<ADB = 122
<ADB = 122/2
<ADB = 61degrees