For this case, the first thing you should keep in mind is:
The solution of the inequation system is given by the shaded region.
Each inequality is met to the right of each graph.
We have then:
For inequation 1:
(2, 6)
(1, -3)
(-2, 5)
For inequation 2:
(2, 6)
(-1,-1)
(-3. 4)
(1, -3)
For the system:
(2, 6)
(1, -3)
Answer:
x, y = 7, 1
Step-by-step explanation:
x+6y=13 ............ (i)
2x+y=15 ........... (ii)
We will apply substitute method.
From equation (i), we can get,
x+6y=13
or, x = 13 - 6y .......... (iii)
Putting the value of x in equation (ii), we can get,
2x+y=15
or, 2 × (13 - 6y) + y = 15
or, 26 - 12 y + y = 15 [multiplying]
or, -11 y = 15 - 26 [Subtracting 26 from both the sides]
or, -11 y = -11
or, [(-11 y) ÷ (-11)] = [(-11) ÷ (-11)] [Dividing both the sides by -11]
or, y = 1
Therefore, the value of y = 1
Putting y = 1 in equation (iii), we get,
x = 13 - 6y
or, x = 13 - 6 × 1
or, x = 13 - 6
or, x = 7
Therefore, the value of x = 7.
Answer: x, y = 7, 1
Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Answer:
4
Step-by-step explanation:
x = 3 meets the requirement x ≥ 1 thus
f(x) = x + 1, so
f(3) = 3 + 1 = 4
Hope this helps
<3
Red
Since in one mile there are 1760 yards, then in 5 miles=1760x5=8800 yards.
