B and c I hoped that helped
Answer:
Step-by-step explanation:
The given data is
42 40 39 31 22 18 15 12 11.7 10.5
Range = 42 - 10.5 = 31.5
Mean = (42 + 40 + 39 + 31 + 22 + 18 + 15 + 12 + 11.7 + 10.5)/10 = 24.12
n = 10
Variance = Summation(x - mean)²/n
Summation(x - mean)² = (42 - 24.12)^2 + (40 - 24.12)^2 + (39 - 24.12)^2 + (31 - 24.12)^2 + (22 - 24.12)^2 + (18 - 24.12)^2 + (15 - 24.12)^2 + (12 - 24.12)^2 + (11.7 - 24.12)^2 + (10.5 - 24.12)^2 = 1452.396
Variance = 1452.396/10 = 145.2396
Standard deviation = √(summation(x - mean)²/n
Standard deviation = √(145.2396
Standard deviation = 12.1
The standard deviation of the sample is not a good estimate of the variation of the salaries of the TV personalities in general because
B. No, because the sample is not representative of the whole population.
Answer:
0.015 = 1.5% of BMW dealers are pricing the BMW 3 Series Coupe 335i at more than the average price ($44,520) for a Mercedes CLK350 Coupe
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What percentage of BMW dealers are pricing the BMW 3 Series Coupe 335i at more than the average price ($44,520) for a Mercedes CLK350 Coupe?
This is 1 subtracted by the pvalue of Z when X = 44520. So



has a pvalue of 0.985
1 - 0.985 = 0.015
0.015 = 1.5% of BMW dealers are pricing the BMW 3 Series Coupe 335i at more than the average price ($44,520) for a Mercedes CLK350 Coupe
Rectangles are similar figures, thus if scaled copies of each other then the ratios of corresponding sides must be equal
compare ratios of lengths and widths
rectangles A and B
k =
=
← ratio of lengths
k =
=
← ratio of widths
scale factors are equivalent, hence rectangle A is a scaled copy of B
rectangles C and B
k =
=
← ratio of lengths
k =
=
← ratio of width
scale factors (k ) are not equal, hence C is not a scaled copy of B
rectangles A and C
k =
=
← ratio of lengths
k =
← ratio of widths
the scale factors are not equal hence A is not a scaled copy of C
Yes, because if you use common Denominator, it'll be 9/10 and 5/10