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Sergeu [11.5K]
3 years ago
10

The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y)^6 are _____.

Mathematics
2 answers:
Kryger [21]3 years ago
5 0
Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
 x ^ 6 + 6x ^ 5y + 15x ^ 4y ^ 2 + 20x ^ 3y ^ 3 + 15x ^ 2y ^ 4 + 6xy ^ 5 + y ^ 6
 Therefore, the coefficients of the expansion are given by:
 1, 6, 15, 20, 15, 6, 1
 Answer:
 
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y) ^ 6 are 1, 6, 15, 20, 15, 6, 1
Ksivusya [100]3 years ago
5 0

Answer:

1, 6, 15, 20, 15, 6, 1

Step-by-step explanation:

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Find 3 consecutive odd integers such that 4 times the sum of the first two is 62 less than the product of -30 and the third.
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Answer:

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Step-by-step explanation:

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A function y = g(x) is graphed below. What is the solution to the equation g(x) = 3? x = 3 3 < x < 5 3 ≤ x ≤ 4 3 ≤ x <
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3 years ago
Which expression is equivalent to StartRoot 120 x EndRoot?.
Irina-Kira [14]

Here for 120, the expression for the start root and end root is given  

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<h3>What will be the expression for start root and enroot of 120?</h3>

Here we need to find \sqrt{120}

By simplifying the given expression, we get:

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by taking square roots on both sides we get

\sqrt{120} =2\sqrt{30}

Thus for 120, the expression for the start root and end root is given  \sqrt{120} =2\sqrt{30}

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