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Fittoniya [83]
4 years ago
13

How much neutrons, protons and electrons does Al3+ have?​

Chemistry
2 answers:
Lady_Fox [76]4 years ago
8 0

n =14

p = 13

e = 10xplanation:

We are presented with an aluminium ion over here

But let's write aluminium's data first

n = 14

p = 13

e = 13

To ionize Al to Al 3+ , 3 e are removed.

Thus, n =14

p = 13

e = 10

Ugo [173]4 years ago
6 0

Answer: Protons = 13

Electrons= 10

Neutrons = 14

Explanation: This problem is an ion of Al which has a charge of +3

For this ion the atomic number for Al is 13 and its mass number is 27.

The atomic number indicates the number of protons which is 13. The number of electrons is changed due to loss of electrons since it was ionized. It loses 3 electrons so the total number of electrons is 13-3 = 10.

The number of neutrons can be calculated using

Atomic mass - atomic number

27- 13 = 14 neutrons

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Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

<u><em>P*V = n*R*T  Equation (A)</em></u>

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

Density allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

Being the molar mass of a substance the mass contained in one mole of said substance, the number of moles can be expressed as:

n=\frac{mass}{molar mass} <em>Equation (B)</em>

Replacing in <u><em>Equation (A)</em></u>:

P*V=\frac{mass}{molar mass} *R*T

Solving to get the definition of density expressed in the equation, you get:

density=\frac{mass}{V} =\frac{P*molar mass}{R*T}

Being:

  • P=0.500 atm
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  • R= 0.082 \frac{atm*L}{mole*K}
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and replacing:

density=\frac{mass}{V} =\frac{0.500 atm*44 \frac{g}{mole} }{0.082 \frac{atm*L}{mole*K} *300 K}

you get:

density= 0.89 \frac{grams}{L}

<em><u>The density of CO₂ gas at 27 Celsius and 0.500 atm is 0.89 </u></em>\frac{grams}{L}<em><u></u></em>

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