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kicyunya [14]
3 years ago
11

As the temperature increases, the molecular motion of the molecules decreases and it

Chemistry
2 answers:
inn [45]3 years ago
8 0

Answer:

true

Explanation:

i'm not so sure

vaieri [72.5K]3 years ago
7 0
The answer would be true
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What is the mole ratio of H2O to C8H8?
zepelin [54]

Answer:

Mole ratio for a compound

The chemical formula tells us the mole ratio.

CO2 = 1 CO2 molecule : 1 C atom : 2 O atoms.

Mole ratio for a reaction

The balanced chemical reactions tells us.

C12H22O11 + 12 O2  12 CO2 + 11 H2O

1 C12H22O11 molecule: 12 O2 molecules : 12 CO2

molecules : 11 H2O molecules.

Applications of the mole ratio concept

grams <--> moles <--> moles <--> grams

Explanation:

4 0
3 years ago
If 200. mL of 0.60 M MgCl2(aq) is added to 400 mL of distilled water, what is the concentration of Mg and Cl in the resulting so
sladkih [1.3K]

Answer:

C. 0.20 M Mg ion & 0.40 M Cl ion

Explanation:

MgCl₂ is a ionic salt which is dissociated as this

MgCl₂  →  Mg²⁺  +  2Cl⁻

First of all, we have a solution of 200 mL, with [MgCl₂] = 0.6M

Molarity . volume = moles.

0.6 mol/l . 0.2l = 0.12 mol

  MgCl₂  →  Mg²⁺  +  2Cl⁻

0.12mol      0.12         0.24

This moles are also in 400mL of water, so the new concentration is

[Mg²⁺] = 0.12 m/0.6L = 0.2M

[Cl⁻] = 0.24 m/0.6L = 0.4M

Remember we initially have 200mL and then, we add 400 mL, so we supose aditive volume. (600mL)

8 0
2 years ago
Elemental mercury combines with oxygen to make mercury oxide. write a balanced equation
Ilia_Sergeevich [38]
Hg + O2 --> HgO + O

Note that Mercury has a variable valency. 

6 0
3 years ago
For a concentration technique, Stotal is given as 19.31 ± 0.035, Smb is 0.22 ± 0.008, and kA is 0.154 ± 0.007 ppm–1, where Stota
professor190 [17]

Answer:

B

Explanation:

8 0
2 years ago
You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y
lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = age of sample  = 6 days

a = initial amount of the reactant  =  1 g

a - x = amount left after decay process   = 0.2 g

a) to find the rate constant

6=\frac{2.303}{k}\log\frac{1.0}{0.2}

k=\frac{2.303}{6}\log\frac{1.0}{0.2}

k=0.268days^{-1}

b) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days

The half life is 2.58 days

3 0
3 years ago
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