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torisob [31]
2 years ago
8

15. An increase in atomic number is related to an increase in atomic mass because

Chemistry
1 answer:
NARA [144]2 years ago
6 0

Answer:

\boxed {\boxed {\sf C. \ More \ protons \ are \ present \ in \ the \ atomic \ nucleus}}

Explanation:

First, let's define <u>atomic number</u>.

    ⇒ The number of <u>protons </u>in an atom.

    ⇒ This number determines the identity and properties of the atom

So, atomic number relates to protons. There is an increase in atomic number, so there must be <u>more</u> protons in the atom. We can eliminate choices A and B, because they pertain to electrons.

We are left with choices C and D. The difference between them is the location of the protons.

Protons are part of the <u>nucleus </u>of the atom: the dense, central region of the atom comprised of nucleons: protons and neutrons.

Electrons, not protons, orbit the nucleus, so  D is not correct.

We are left with choice C: <u>more protons are present in the atomic nucleus </u>

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Convert 281 K to degrees Celsius.<br><br> 281 K = _____<br><br> -8°C<br> 554°C<br> 8°C
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Barium sulfate is made by the following reaction.
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                      %age Yield =   96 %

Explanation:

                    The balance chemical equation for given double replacement reaction is,

                      Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2 NaNO₃

Step 1: <u>Calculate moles of Ba(NO₃)₂:</u>

Moles  =  Mass / M.Mass

Moles  =  75.1 g / 261.33 g/mol

Moles  =  0.2873 moles of Ba(NO₃)₂

Step 2: <u>Find out moles of BaSO₄ formed:</u>

According to balance chemical equation,

                  1 mole of Ba(NO₃)₂ produced  =  1 mole of BaSO₄

So,

        0.2873 moles of Ba(NO₃)₂ will produce  =  X moles of BaSO₄

Solving for X,

                      X =  0.2873 mol × 1 mol / 1 mol

                       X =  0.2873 moles of BaSO₄

Step 3: Calculate Theoretical Mass of BaSO₄:

Mass  =  Moles × M.Mass

Mass  =  0.2873 mol × 233.38 g/mol

Mass  = 67.07 g of BaSO₄

Step 4: <u>Calculate %age Yield as:</u>

                 Theoretical Yield  =  67.07 g

                  Actual Yield  =  64.4 g

                  %age Yield  =  <u>???</u>

Formula Used:

                   %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

Putting Values,

                   %age Yield  =  (64.4 g ÷ 67.07 g) × 100

                   %age Yield =  96.01 % ≈ 96 %

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