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3 years ago

Given the following table find the equation that matches it

Mathematics

1 answer:

zzz [600]3 years ago

5 0

Answer:

Y=2x+1

1 is the y and the 2 is the x value since every 2 blocks down and 1 over it will hit a corner or edge of box. Hopefully this helps

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PLEASE HELP NOW!! If K is the set of all letters in the word “equation”, and L is the set of all letters of the word “inequality

satela [25.4K]

Answer:

e,q,u,a,t,i,n & EQUATIONYL

Step-by-step explanation:

K∩L:

First write both the words, equation and inequality down.

E Q U A T I O N

I N E Q U A L I T Y

You can see EQUATIN repeats in both of the words.

K∪L:

First write both the words, equation and inequality down.

E Q U A T I O N

I N E Q U A L I T Y

This time just write down all the letters EXCEPT the ones that repeat. EQUATIONYL

6 0

3 years ago

HELP HELP HELP OVER HERE EXTRA POINTS

Evgesh-ka [11]

Answer:

Step-by-step explanation:

the median of july is 8

the median of august is 10

median=middle number

6 0

4 years ago

Which expression is equivalent to 24 ⋅ 2−7?

marta [7]

Answer:

211

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The quotient of six and one

Nastasia [14]

A quotient of a number and 6

Explanation: Quotient means that you divide something by another. Let's let n be the "number". Therefore, "a quotient of a number and 6" refers to n6 or n÷6 .

6 0

2 years ago

Read 2 more answers

A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =

tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

$f(x)=-16x^2+64x+5$

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

$10=-16x^2+64x+5$

Subtracting 10 from both sides:

$-16x^2+64x-5=0$

For simplicity, divide both sides by -1:

$16x^2-64x+5=0$

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute:

$\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}$

Evaluate:

$\displaystyle x=\frac{64\pm\sqrt{3776}}{32}$

Simplify the square root:

$\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}$

Therefore:

$\displaystyle x=\frac{64\pm8\sqrt{59}}{32}$

Simplify:

$\displaystyle x=\frac{8\pm\sqrt{59}}{4}$

Approximate:

$\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08$

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0

3 years ago