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algol13
4 years ago
15

A fully-booked hotel has 62 guest in 35 rooms, some in single rooms, and some in double rooms. How many single and double rooms

are there in the hotel? (It's with equations)
Mathematics
1 answer:
Lunna [17]4 years ago
6 0

Answer:

In this hotel there are 27 double rooms and 8 single rooms.

Step-by-step explanation:

We will consider the guests who stayed on double rooms as 'd' and the ones who stayed on single rooms as 's'. The sum of them should be the number of guests on the hotel. So we have:

s + d = 62

They need to be distributed in such a way that they'll fit in 35 rooms. The people who got on double rooms need to be divided by two, since two people will be on the same room. So we have:

s + d/2 = 35

Since we have two equations and two variables we can create a system of equations and solve it:

s+ d = 62

s + d/2 = 35

From the first equation we have:

s = 62 - d

Swaping this value on the second equation:

62 - d + d/2 = 35

62 -d/2 = 35

-d/2 = 35 - 62

-d/2 = -27

-d = -54

d = 54

Using that value we can solve for s:

s = 62 - 54 = 8

So they had 54 people staying on double rooms and 8 people staying on single rooms. Since 54 people stayed on double rooms there are 27 double rooms.

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sineoko [7]

Answer:

See picture.

Sorry about the scrawly handwriting!

Step-by-step explanation:

You can split the figure into 2 trapezoids as shown.

5 0
3 years ago
3. A new process has been developed for applying pho­ toresist to 125-mm silicon wafers used in manufac­ turing integrated circu
dlinn [17]

Answer:

a

The null hypothesis is  H_o : \mu  =  13.4000

The alternative hypothesis is  H_a :  \mu \ne  13.4000

The null hypothesis is rejected

b

The  99% confidence level is   13.3930  < \mu  < 13.3994

Step-by-step explanation:

From the question we are told that

  The sample size is  n =  10

   The  population mean is  \mu =  13.4 000 \  angstroms

   The level of significance is  \alpha =  0.05

   The  sample data is  

13.3987, 13.3957, 13.3902, 13.4015, 13.4001, 13.3918, 13.3965, 13.3925, 13.3946, and 13.4002

Generally the sample mean is mathematically represented as

        \= x =  \frac{13.3987+ 13.3957\cdots +13.4002 }{10}

=>     \= x = 13.3962

Generally the sample standard deviation  is mathematically represented as

    \sigma = \sqrt{\frac{\sum (x_i - \= x)^2}{n} }

=> \sigma = \sqrt{\frac{ (13.3987 - 13.3962)^2 +  (13.3987 - 13.3962)^2 + \cdots + (13.3987 -13.4002)^2  }{10} }

=>  \sigma =0.0039

The null hypothesis is  H_o : \mu  =  13.4000

The alternative hypothesis is  H_a :  \mu \ne  13.4000

Generally the test statistics is mathematically represented as

      z  =  \frac{\= x - \mu}{\frac{\sigma}{\sqrt{n} } }

=>    z  =  \frac{13.3962 -  13.4000}{\frac{0.0039}{\sqrt{10} } }

=>   z =  3.08

Generally the p-value is mathematically represented as

       p-value  = 2P( z   >  3.08)

From the z-table  P(z >  3.08)= 0.001035

So

       p-value  = 2* 0.001035

      p-value  = 0.00207

So from the obtained value we see that

     p-value  < \alpha

Hence the null hypothesis is rejected

Consider the b question

Given that the confidence level is  99%  then the level of significance is

    \alpha =  (100 -99)\%

=> \alpha =  0.01

Generally from the normal distribution table critical value  of  \frac{\alpha }{2} is  

    Z_{\frac{\alpha }{2} } =  2.58

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>   E = 2.58  *  \frac{0.0039}{\sqrt{10} }

=>    E = 0.00318

Generally the 99% confidence interval is mathematically represented as

     13.3962   - 0.00318  < \mu  < 13.3962   +  0.00318

=>   13.3930  < \mu  < 13.3994

 

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3 years ago
In the image, the distance from the swings to the slide is 35
Nikitich [7]
The Pythagorean theorem is a^2+b^2=c^2 where a and b are legs and c is the hypotenuse(longest side). you haven’t put a picture so I don’t know where 35 is a leg or the hypotenuse, but all you have to do is square the 2 shorter sides and add them and set it equal to the square of the longer side. You can do it!
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A bucket holds b liters of water. But a jar holds 8 fewer liters than the bucket. How many times can the bucket hold than the ja
kykrilka [37]

Answer:

b / (b - 8)

Step-by-step explanation:

Given that :

Litres of water held by bucket = b

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The number of times bucket can hold than jar is :

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b / (b - 8)

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