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son4ous [18]
3 years ago
15

Which is the graph of f(x) =2(3)x^

Mathematics
2 answers:
worty [1.4K]3 years ago
7 0

Answer:

Its A

Step-by-step explanation:

pentagon [3]3 years ago
5 0

Answer:

the first graph on the left

Step-by-step explanation:

Substitute the x- coordinate of the point indicated on the graph into the equation and check that this gives the value of the y- coordinate

(1, 6) ⇒ f(1) = 2(3)^{1} = 2 × 3 = 6 ← correct

(1, 9) gives y = 6 ≠ 9 ← not valid

(2, 8) ⇒ f(2) = 2(3)^{2} = 2 × 9 = 18 ≠ 8 ← not valid

(2, 12) gives y = 18 ≠ 12 ← not valid

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Tanner earns $14.50 per hour for the first 8 hours he works each day. For every hour worked over 8, he earns 1.75 of his normal
bogdanovich [222]

Answer:

167.19

14.50 x 8 = 116.00

14.50 + 1.75 = 16.25 per hour overtime

16.25 × 3.15 hour overtime = 51.19

116.00 + 51.19 = 167.19

Step-by-step explanation:

7 0
3 years ago
Can someone please help, I'll give brainliest!!! WORTH 40 PTS!
Studentka2010 [4]

Answer:

X = 14.48528137

Step-by-step explanation:

  1. ADD 72 TO BOTH SIDES
  2. SQUARE ROOT 72
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5 0
3 years ago
IDK this I really need help with this if anyone wants to help plz do
LUCKY_DIMON [66]
(b+5)(b-7)
hope it can help u
5 0
3 years ago
a hardware store has 568 nails in 8 bins. each bin has the same number of nails. how many nails are in each bin? Luke solve this
stiks02 [169]

Answer:

No

Step-by-step explanation:

Because you have to multiply 568 x 8 to get 4084 but when u multiply it u get 2272

8 0
3 years ago
Please please help me
Alex73 [517]

Answer:

x = 5.5

Step-by-step explanation:

Given 2 secants intersecting the circle from a point outside the circle then

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

x(x + 14) = 6(6 + 12)

x² + 14x = 6 × 18 = 108 ( subtract 108 from both sides )

x² + 14x - 108 = 0 ← in standard form

with a = 1, b = 14 and c = - 108

Using the quadratic formula to solve for x

x = ( - b ± \sqrt{b^2-4ac} ) / 2a

  = ( - 14 ± \sqrt{14^2-(4(1)(-108)} ) / 2

  = ( - 14 ± \sqrt{196+432} ) / 2

  = ( - 14 ± \sqrt{628} ) / 2

  x = \frac{-14-\sqrt{628} }{2} or x = \frac{-14+\sqrt{628} }{2}

  x = - 19.5 or x = 5.5 ( to 1 dec. place )

However x > 0 ⇒ x = 5.5

6 0
3 years ago
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