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Scrat [10]
3 years ago
8

What is the equation, in point-slope form, for a line that goes through ​ (2, −6)​ and has a slope of ​ −3\4 ​ ?

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
Y - y1 = m(x - x1)
slope(m) = -3/4
(2,-6)...x1 = 2 and y1 = -6
now we sub...pay close attention to ur signs
y - (-6) = -3/4(x - 2)...not done yet
y + 6 = -3/4(x - 2) <===
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Find the missing value in each figure below. What does “y” equal?
finlep [7]

Answer:

Step-by-step explanation:

The perpendicular is equal to 6. That's because the left triangle's missing angle is 180 - 45 -90 = 45

The angle in the right triangle is given as 52.

The cos(52) = adjacent side (which we just found to be 6) / y

Multiply both sides by y

y cos(52) = 6

cos(52) = 0.6157

Divide by sides by cos(52)

y = 6 / cos(52)

y = 6 / 0.6157

y = 9.76

8 0
3 years ago
What’s 22,000 - 407% of 60?
DENIUS [597]

Answer:

21,755.8

Step-by-step explanation:

To solve this equation, we must first find 407% of 60.

To do this, place the percent over 100 (fraction form), then, multiply it by the number you're finding the percentage of.

407/100 x 60/1 = 24,420/100

24420 / 100 = 244.2

244.2 is 407% of 60.

Lastly, you subtract 244.2 from 22,000.

22,000 - 244.2 = 21,755.8

4 0
3 years ago
How to I solve problem 1?
Verdich [7]
#1

The uniforms are numbered 0, 1, 2, ..., 99. That's 100 numbers. Half of them are odd and half of them are even. So the probability that any one of the uniforms is odd is 1/2 just like the probability that any one uniform is even is 1/2.

(a) The numbers on the uniforms are independent of one another. That is, the number of her cross-country uniform does not in any way determine the number on her basketball uniform and vice versa. This means that we can find the probability that each is odd and multiply these together using what is called the counting principle. The probability that all are odd is:
(1/2)(1/2)(1/2)=1/8

(b) This is done the same way we did part (a). Since the probability of any one uniform being odd is the same as it being even (1/2), the answer here is the same: (1/2)(1/2)(1/2)=1/8

(c) This problem differs from that in (a) and (b). There is only one way for all three uniforms to be odd numbers: (odd, odd, odd) or all even (even, even, even). However, there are multiple ways for the uniforms to be two odd and one even. If the uniforms are listed in order: cross-country, basketball, softball we can get exactly one even in any of three ways:
even, odd, odd
odd, even, odd
odd, odd, even
The probability for any one of these possibilities is (1/2)(1/2)(1/2)=1/8 but since there are three way the probability that we get even exactly once is equal to (3)(1/8) = 3/8
7 0
3 years ago
HELP!!<br>Find the third term of (x^2+3y)^3
lana66690 [7]

Answer:

T_{3}=27{x}^{2}y^2

Step-by-step explanation:

The given binomial expression is:

( {x}^{2} + 3y)^{3}

When we compare to:

{(a +b)}^{n}

We have

a =  {x}^{2}

b = 3y \\ n = 3

The nth term is given by;

T_{r+1}=^nC_ra^{n-r}b^r

To find the 3rd term, we put:

r + 1 = 3 \\ r = 2

We substitute into the formula to get:

T_{3}=^3C_2( {x}^{2} )^{3-2}(3y)^2

We simply:

T_{3}=3( {x}^{2} )^{1} \times 9y^2

T_{3}=27{x}^{2}y^2

3 0
3 years ago
1+2-3+4+5-6+7+8-9...+97+98-99
zaharov [31]

Answer:

  1584

Step-by-step explanation:

The sum of this sequence can be found a number of ways. One way is to recast it as the series whose terms are groups of three terms of the given series.

__

<h3>series of partial sums</h3>

The partial sums, taken 3 terms at a time, are

  1+2-3 = 0

  4+5-6 = 3

  7+8-9 = 6

...

  97+98-99 = 96

So the original series is equivalent to ...

  0 +3 +6 +... +96 = 3×1 +3×2 +... +3×32 = 3×(1 +2 +... +32)

That is, the sum is 3 times the sum of the consecutive integers 1..32.

__

<h3>consecutive integers</h3>

The sum of integers 1..n is given by the equation ...

  s(n) = n(n+1)/2

__

<h3>series sum</h3>

Using this to find the sum of our series, we find it to be ...

  series sum = 3 × (32)(33)/2 = 1584

_____

<em>Alternate solution</em>

The given series is the sum of integers 1-99, with 6 times the sum of integers 1-33 subtracted. That is, ...

  1 + 2 - 3 + 4 + 5 - 6 = 1+2+3+4+5+6 -2(3 +6) = 1+2+3+4+5+6 -6(1+2)

Continuing on to ...97 +98 -99 gives the result s(99) -6s(33).

Computed that way, we find the sum to be ...

  (99)(100)/2 -6(33)(34)/2 = 4950 -3366 = 1584

3 0
2 years ago
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