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Klio2033 [76]
4 years ago
15

A recipe for 6 dozen cookies calls for 3/4 cup of sugar. How much sugar is needed to make 4 dozen cookies? pls show all work and

answer
Mathematics
1 answer:
Paraphin [41]4 years ago
4 0
So if 6 dozen cookies needs 3/4 cup of sugar, and we need to know how much sugar is needed to make 4 dozen, then find how much of 6 dozen 4 dozen is.

To do this, put it as a fraction:

4 dozen / 6 dozen, or 4/6, which is 2/3.

Since conveniently it calls for 3/4 cup of sugar, we can multiply that by 2/3, and we'll get 6/12, or 1/2.

So 1/2 cup of sugar is needed for 4 dozen cookies.
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A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is
xxTIMURxx [149]

Answer:

The test contains 10 three-point questions and 14 five-point questions.

Step-by-step explanation:

We can substitute a definition of one of the variables by rearranging the first equation.

We set the first equation equal to one of our two variables.

y = 24 - x

Now we substitute this equality into our second equation

3x + 5(24 - x) = 100

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3 years ago
Find the length of AB, given that be is a median of the triangle and AC = 30.
RSB [31]

SOLUTION

Draw the diagram

a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side.

Hence

|DB|\text{ bisect |AC|}

SInce AC=30, Then

\begin{gathered} AB=15,\text{ CB= 15} \\ \text{Hence} \\ |AB|=15 \end{gathered}

Thus, from the median properties of a triangle, AB = 15

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1 year ago
Triangle ABC is the image of Triangle DEF under a dilation such that AB=3/4 DE. Which of the following best describes Triangles
koban [17]

Answer:

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7 0
2 years ago
The attendance at baseball games at a certain stadium is normally distributed, with a mean of 30,000 and a standard deviation of
lakkis [162]

Answer:

a) 0.964

b) 0.500

c) 0.885

d) x \geq 32467.5

e) 0.997      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30000

Standard Deviation, σ = 1500

We are given that the distribution of attendance at stadium is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(attendance is greater than 27,300)

P(x > 27300)

P( x > 27300) = P( z > \displaystyle\frac{27300 - 30000}{1500}) = P(z > -1.8)

= 1 - P(z \leq -1.8)

Calculation the value from standard normal z table, we have,  

P(x > 27300) = 1 - 0.036 = 0.964 = 96.4\%

b) P(attendance greater than or equal to 30000)

P(x > 30000) = P(z > \displaystyle\frac{30000-30000}{1500}) = P(z \geq 0)\\\\P( z \geq 0) = 1 - P(z \leq 0)

Calculating the value from the standard normal table we have,

1 - 0.500 = 0.500 = 50\%

c) P(attendance between 27000 and 32000)

P(27000 \leq x \leq 32000) = P(\displaystyle\frac{27000 - 30000}{1500} \leq z \leq \displaystyle\frac{32000-30000}{1500}) = P(-2 \leq z \leq 1.33)\\\\= P(z \leq 1.33) - P(z < -2)\\= 0.908 - 0.023 = 0.885 = 88.5\%

P(27000 \leq x \leq 32000) = 88.5\%

e) P(attendance less than 33000)

P(x < 33000)

P( x < 33000) = P( z < \displaystyle\frac{33000 - 30000}{1500}) = P(z < 2)

Calculating the value from the standard normal table we have,

P(x < 33000)  = 0.997 = 99.7%

d) We have to find x such that:

P( X > x) = P( z > \displaystyle\frac{x - 30000}{1500}) = 0.95

Calculating the value from the standard normal table we have,

P(z = 1.645) = 0.95

Thus,

\displaystyle\frac{x - 30000}{1500} \geq 1.645\\\\x \geq 32467.5

The attendance should be greater than or equal to 32467.5 to be in the top 5% of all games.

6 0
4 years ago
Can someone please explain this by step by step? And give me the answer
AURORKA [14]

Answer:

we know that q=-18

So if we see the fraction below it says q/3

We know that q is -18

Therefore, you substitute it in for q and you get

-18/3 which equals -6

7 0
3 years ago
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