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Alina [70]
3 years ago
15

Do ΔCBG and ΔFEG in the figure appear to be similar? Why or why not?

Mathematics
2 answers:
astra-53 [7]3 years ago
8 0

Answer:

C

Step-by-step explanation:

They're not similar because only one pair of corresponding angles in the two triangles is congruent.

Mama L [17]3 years ago
6 0

Answer: Option C. They're not similar because only one pair of corresponding angles in the two triangles is congruent.

Solution:

The only one pair of corresponding angles in the two triangles is congruent is the angle BGC in ΔCBG and the angle FGE in ΔFEG, because they are vertical angles (opposite by the vertex)

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marishachu [46]

Answer:66

Step-by-step explanation:

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2 years ago
Find the scale factor.
charle [14.2K]

Answer:

2/9

Step-by-step explanation:

Scale factor = 10/45 = 2/9

6 0
3 years ago
A rental car agency charges $30.00 per day
lutik1710 [3]
<h2>Answer:</h2><h2>They should travel 120 mils in one day for both rental agencies  to cost the same amount to rent</h2>

Step-by-step explanation:

A rental car agency charges $30.00 per day  plus per mile $0.15.

Let x be the number of miles travelled by car

Their total cost = 30 + (0.15x)   ... (1)

Another rental car  agency charges $36.00 per day plus $0.10  per mile

Their total cost = 36 + (0.10x)   ... (2)

Equating (1) and (2), we get

30 + (0.15x) = 36 + (0.10x)

36 - 30 = 0.15x - 0.10x

6 = 0.05x

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They should travel 120 mils in one day for both rental agencies  to cost the same amount to rent

5 0
3 years ago
Compute $\sqrt{25^2-7^2}$.
EastWind [94]

Answer:

24

Step-by-step explanation:

\sqrt{25^2-7^2}\\\\=\sqrt{(25-7)(25+7)}\\\\=\sqrt{18(32)}\\\\=\sqrt{9*2*2^5}\\\\=\sqrt{3^2\cdot 2^6}\\\\=\sqrt{(3\cdot2^3)^2}\\\\=3\cdot2^3\\\\=3\cdot8\\\\=24

5 0
2 years ago
Is there a easy way to subtract fractions with unlike deiomaters
Angelina_Jolie [31]

Answer:

Yes

Step-by-step explanation:

It's just like adding fractions where you have to find the common denominator so the fractions can be subtracted.

<u>Example</u>

<u />\displaystyle \frac{1}{2}-\frac{1}{3}=\frac{1*3}{2*3}-\frac{2*1}{2*3}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}

8 0
2 years ago
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