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Murljashka [212]
3 years ago
11

What is 18:4 equivalent to

Mathematics
2 answers:
Serhud [2]3 years ago
5 0
9:2 is equivalent to 18:4
NeX [460]3 years ago
3 0
It's equivalent to 9:2
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One crate can hold 8 cases of trading cards.How many crates are needed to hold 128 cases of trading cards?
Lunna [17]
16 crates to hold all 128  cases of trading cards

7 0
2 years ago
A rectangle has a length of x+7 and a width of x-3. write and expression that represents the AREA of the rectangle.
Lyrx [107]

Answer:

A = x^2 + 4x -21

Step-by-step explanation:

L = x+7

W = x-3

A = L*W

A = (x+7)(x-3)

A = x^2 + 4x - 21

6 0
3 years ago
There is 4/5 of a litre of milf in a jar. If Sue pours out 250 ml of milk from the jar, how much milk will be left?
Shalnov [3]
1 litre=1000 ml. 1000-250=750. That's your answer.
3 0
3 years ago
Read 2 more answers
A statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after
lana [24]

Answer:

95% confidence interval estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

(a) Lower Limit = 0.486

(b) Upper Limit = 0.624

Step-by-step explanation:

We are given that a statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after receiving their bachelor's.

She took a random sample of 200 graduates from the class of 1979 and determined their occupations in 1989. She found that 111 persons were still employed primarily as engineers.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                         P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of persons who were still employed primarily as engineers  = \frac{111}{200} = 0.555

           n = sample of graduates = 200

           p = population proportion of engineers

<em>Here for constructing 95% confidence interval we have used One-sample z proportion test statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                 significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.555-1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } , 0.555+1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } ]

 = [0.486 , 0.624]

Therefore, 95% confidence interval for the estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

7 0
3 years ago
Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?
Fynjy0 [20]

Answer:

-(x-4)^{2}

or -x^{2}+8x-16

Step-by-step explanation:

Given a second degree polynomial has a root 4 with multiplicity 2

That means, 4 is a repeating root of the polynomial.

Any second degree polynomial has at most 2 real roots.

⇒Both roots of the polynomial are 4.

and its expression can be written as c·(x-4)^{2} where c is a real number

⇒c·(x^{2}-8x+16)

⇒cx^{2}-8cx+16c

Also, the leading coefficient is given as -1

So, c = -1

and the expression becomes (-1)x^{2}-8·(-1)·x+16·(-1)

⇒<u>-x^{2}+8x-16</u>

7 0
3 years ago
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