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3 years ago

8

Jasmine has 3/4 cup of flour in a mixing bowl. After adding more flour to the mixing bowl, Jasmine says that she now has 5/8 cup

of flour.
Why is her statement incorrect?

1 answer:

Lera25 [3.4K]3 years ago

4 0

Answer:

6/8

Step-by-step explanation:

3/4 into eighths would be 6/8. She said she had 5/8 cups of flour.

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What is one-fourth of the circumference of a circle that measures 12 centimeters around?

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3

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12cm / 4 = 3cm

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M(2,5) is the midpoint of RS. The coordinates of S are (3,9). What are the coordinates of R?

kobusy [5.1K]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ R(\stackrel{x_1}{x}~,~\stackrel{y_1}{y})\qquad S(\stackrel{x_2}{3}~,~\stackrel{y_2}{9}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{3+x}{2}~~,~~\cfrac{9+y}{2} \right)~~=~~\stackrel{M}{(2~,~5)}\implies \begin{cases} \cfrac{3+x}{2}=2\\[1em] 3+x=4\\ \boxed{x = 1}\\ \cline{1-1} \cfrac{9+y}{2}=5\\[1em] 9+y=10\\ \boxed{y=1} \end{cases}$

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=15%20x%5E%7B2%7D%20%2B14x-49%3D0" id="TexFormula1" title="15 x^{2} +14x-49=0" alt="15 x^{2} +1

Alex777 [14]

$15x^2+14x-49=0\\\\
Terms:\\
a=15\ \ \ \ b=14\ \ \ \ c=-49\\
Quadratic\ Formula:\\\\
x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\
x=\dfrac{-14\pm\sqrt{196+2,940}}{30}\\\\
x=\dfrac{-14\pm\sqrt{3,136}}{30}\\\\
x=\dfrac{-14\pm56}{30}$

$Roots:\\\\
x'=\dfrac{-14+56}{30}\\\\
x'=\dfrac{42}{30}\\\\
x'=\dfrac{21}{15}\\\\
\boxed{x'=\dfrac{7}{5}}\\\\\\\\
x''=\dfrac{-14-56}{30}\\\\
x''=\dfrac{-70}{30}\\\\
\boxed{x''=\dfrac{-7}{3}}$

8 0

3 years ago

Read 2 more answers

Simplify -12+8+5+(-9)

Zinaida [17]

FIRST Remove parentheses.
−12+8+5-9

Simplify -12+8 to -4

-4 + 5 — 9

Simplify
−4 + 5 −4+5 to 1
1 — 9

Simplify

-8 is your answer

3 0

3 years ago

Read 2 more answers

I need help on this problem. I got half of it right but I don’t know how I got the last answer wrong... Can anyone please help m

morpeh [17]

I got the same answer as you. Try to ask your teacher about it since it’s a math problem online or something.

8 0

3 years ago