11/4 times 12/1 equals 132/4. So the employee gets 132/4 vacation days every year.
Answer:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Step-by-step explanation:
For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Answer:
The answer will be 85,968
9514 1404 393
Answer:
- c = 2
- segments 10, 8, 6 (top down)
Step-by-step explanation:
The sum of top and bottom bases is twice the midsegment.
(c² +6) +(c² +2) = 2(4c)
2c² -8c +8 = 0 . . . . . . . . . subtract 8c
2(c -2)² = 0 . . . . . . . . factor
c = 2 . . . . . . the value that makes the binomial be zero
The value of c is 2; the segment lengths (top-down) are 10, 8, 6.