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Nutka1998 [239]
3 years ago
12

a city council has 12 members. Five are democratss and seven are republicans. How many ways can a four member comitte be selecte

d?
Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer: 495ways

Step-by-step explanation:

Selecting some b people from a group of people are based on combination principle.

If we are selecting "r'' people from a total number of 'n' people, we will have;

nCr = n!/(n-r)!r!

Since 4 people are to be selected from a committee of 5democrats and 6republicans,

Note that the question is not specific as to how many from Republicans and Democrats to select that will make the 4people,

Therefore, the selection can be done in this manner

- 0people from democrats and 4peoples from Republicans

5C0 × 7C4 = 5!/5!0! × 7!/3!4!

= 1×35= 35ways

- 1people from democrats and 3peoples from Republicans

5C1 × 7C3 = 5×35 = 175ways

- 2peoples from democrats and 2peoples from Republicans

5C2 × 7C2 = 10 × 21 = 210ways

- 3peoples from democrats and 1people from Republicans

5C3 × 7C1 = 10 × 7 = 70ways

- 4peoples from democrats and 0people from Republicans

5C4 × 7C0 = 5 × 1 = 5ways

Adding all possible combinations

35+175+210+70+5

= 495ways

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4 years ago
find the range for the measurement of the third side of a triangle given two sides are 8.6 km and 14.5 km
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Answer:

Third side of the triangle should be larger than 5.9 km, and smaller than 23.1 km

Step-by-step explanation:

Let's examine the two extreme cases for any possible triangle that has two known sides and one larger than the other one. The attached figure tries to represent those extreme cases.

In the first depicted case, the third side (shown in red) is barely larger than the difference between the known sides (shown in green). So for this case we have that the third side must be > 14.5 km - 8.6 km

that is : third side > 5.9 km

In the opposite case, when we place the two known sides (shown in green) almost opposite to each other, the measure of the third side is almost (but not quite) the addition of the known sides.

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7 0
4 years ago
The viscosity of a liquid detergent is supposed to average 800 centistokes at 25° C. A random sample of 16 batches of detergent
meriva

Answer:

a) Null hypothesis:\mu = 800        

Alternative hypothesis:\mu \neq 800  

b) z=\frac{812-800}{\frac{25}{\sqrt{16}}}=1.92    

c) p_v =2*P(z>1.92)=0.0548    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not different from the value of 800.

d) 812- 1.96 \frac{25}{\sqrt{16}}=799.75

812+ 1.96 \frac{25}{\sqrt{16}}=824.25

Since the confidence interval contains the value 800 this result agrees with the result obtained in the hypothesis test we fail to reject the null hypothesis that the true mean is 800

Step-by-step explanation:

Data given and notation        

\bar X=812 represent the mean for the sample    

\sigma=25 represent the standard deviation for the population      

n=16 sample size        

\mu_o =800 represent the value that we want to test      

\alpha represent the significance level for the hypothesis test.      

z would represent the statistic (variable of interest)        

p_v represent the p value for the test (variable of interest)    

a) State the null and alternative hypotheses.        

We need to conduct a hypothesis in order to determine if the true mean is different from 800 centistokes:      

Null hypothesis:\mu = 800        

Alternative hypothesis:\mu \neq 800        

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:        

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)        

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

b) Calculate the statistic        

We can replace in formula (1) the info given like this:        

z=\frac{812-800}{\frac{25}{\sqrt{16}}}=1.92        

c) Calculate the P-value        

Since is a two tailed test the p value would be:        

p_v =2*P(z>1.92)=0.0548    

Conclusion        

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not different from the value of 800.

d) Confidence interval

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing we got:

812- 1.96 \frac{25}{\sqrt{16}}=799.75

812+ 1.96 \frac{25}{\sqrt{16}}=824.25

Since the confidence interval contains the value 800 this result agrees with the result obtained in the hypothesis test we fail to reject the null hypothesis that the true mean is 800

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