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Bond [772]
3 years ago
8

Never mind my question but free brainiest

Mathematics
2 answers:
Sav [38]3 years ago
6 0

What is your question?

sergeinik [125]3 years ago
4 0

Answer:

i want the big brain

Step-by-step explanation:

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If a = √3-√11 and b = 1 /a, then find a² - b²​
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If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

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\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
1 year ago
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