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3 years ago

What is 3+3+573=x+747488448=X

Mathematics

1 answer:

attashe74 [19]3 years ago

3 0

That is not even a question lol

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Add the following complex numbers:

Fittoniya [83]

Answer:

option c

Step-by-step explanation:

(4 - 2i) + (12 + 7i)

multiply the brackets first

4 - 2i + 12 + 7i

combine like terms

16 + 5i

3 0

3 years ago

Read 2 more answers

Can someone help me with this question? I'm kinda stuck. Could you explain it to me? ASAP?!?!!!!!!!!!

Vlad1618 [11]

The answer is on Chegg.com

3 0

3 years ago

A 90-inch length of ribbon is to be cut into three pieces. The longest piece is to be 30 inches longer than the shortest piece,

Free_Kalibri [48]

Lets name the shortest piece a, the medium b and the longest c

Together they are 90inches
$a + b + c = 90$
The longest is 30 inches longer than the shortest
$c = a + 30$
The third piece is half the lenght of the longest
$b = \frac{c}{2}$

So if you place c=a+30 in the other 2 equasions you get

$a + b + (a + 30) = 90 = 2a + b + 30$
And
$b = \frac{30 + a}{2}$
Now if you put this 2 toghether u get
$2a + \frac{30 + a}{2} + 30 = 90$
Multyplied by 2
$4a + 30 + a + 60 = 180$
$5a = 90$
Meaning that a=18inches

Now that we have the lenght of a we put it in the previous equasion

$b = \frac{30 + 18}{2}$
So b=48/2 which means b=24inches

And together they must be 90 so

$18 + 24 + c = 90$

C=48inches

6 0

3 years ago

HELP<br>2 (3x-7)=-4x-6+9x-8

Leni [432]

2 (3x - 7) = -4x - 6 + 9x - 8 Simplify 2 (3x - 7)
6x - 14 = -4x - 6 +9x - 8 Combine like terms (-4x and 9x) (-6 and -8)
6x - 14 = 5x - 14 Subtract 5x from both sides
x - 14 = -14 Add 14 to both sides
x = 0

Check your answer.

2 (3x - 7) = -4x - 6 + 9x - 8 Substitute x for 0
2 (3(0) - 7) = -4(0) - 6 + 9(0) - 8 Multiply 3(0)
2 (0 - 7) = -4(0) - 6 + 9(0) - 8 Multiply -4(0)
2 (0 - 7) = 0 - 6 + 9(0) - 8 Multiply 9(0)
2 (0 - 7) = 0 - 6 + 0 - 8 Subtract (0 - 7)
2(-7) = 0 - 6 + 0 - 8 Multiply 2(-7)
-14 = 0 - 6 + 0 - 8 Get rid of the unneccesary 0s
-14 = -6 - 8 Subtract (-6 - 8)
-14 = -14

So, x = 0 .

5 0

3 years ago

Between what two consecutive integers is 152

TEA [102]

Answer:

152 lies between two consecutive integers 151 and 153.

Step-by-step explanation:

Let n be the given integer.

The predecessor of any integer n is given by n-1.

Similarly the successor of an integer n is given by n+1.

For example: Let n be 100

Then its predecessor is 100-1 = 99

Its successor is 100+1 = 101

In the given question, n=152.

Predecessor of 152 = 152 - 1 = 151

Successor of 152 = 152 + 1 = 153

So 152 lies between two successive integers 151 and 153.

6 0

3 years ago