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3 years ago

14

F (x) = – x2 + 4x + 1

2 answers:

liq [111]3 years ago

8 0

Answer:

The 2 solutions are 0 and 3,

Step-by-step explanation:

– x2 + 4x + 1 = x + 1

-x^2 + 3x = 0

x(-x - 3)

x = 0 or -x - 3 = 0 which gives x = 3.

lora16 [44]3 years ago

6 0

Answer:

x = 0 or x = 3

Step-by-step explanation:

if f(x) = g(x) then – x2 + 4x + 1 = x + 1

add the like terms

-x^2 +3x = 0

-x (x-3) = 0 then x is either 0 or 3

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postnew [5]

$2 \frac{5}{8} \div 2 \frac{1}{2}$
Change the mixed fractions to improper fractions.
To do this, multiply the whole number part by the denominator. Add that to the numerator. Then write the result on top of the denominator.

You would now have:
$\frac{21}{8} \div \frac{5}{2}$
Change the division sign to a multiplication sign by turning the second fraction upside down.
That is,
$\frac{21}{8} \times \frac{2}{5}$

The answer is:
$\frac{42}{40}$

This can be simplified to:
$\frac{21}{20}$

8 0

3 years ago

The formula for converting temperatures in degrees Celsius to degrees Fahrenheit is F = 95C + 32. If the temperature is 20°C, wh

Sveta_85 [38]

Answer:

68 degrees fahrenheit

4 0

2 years ago

Question 24 (1 point)

Aleksandr-060686 [28]

9514 1404 393

Answer:

(a) y = 5

Step-by-step explanation:

The equation of a horizontal line can be written as ...

y = constant

In order to make that line pass through a given point, the constant must match the y-coordinate of the point. Here, that is 5.

y = 5

7 0

2 years ago

Enter a recursive rule for the geometric sequence?

Greeley [361]

Answer:

Step-by-step explanation:

a^1=-2

a^n=a×a^n-1

6 0

2 years ago

Radioactive Decay:

Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}$

The formula used to calculate the time period for a first order reaction follows:

$t=\frac{2.303}{k}\log \frac{a}{(a-x)}$

where,

k = rate constant = $0.01506days^{-1}$

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

$t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days$

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0

2 years ago