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blagie [28]
3 years ago
10

What inequality represents the verbal expression?

Mathematics
2 answers:
Viktor [21]3 years ago
6 0
The second one, x < 70
horrorfan [7]3 years ago
3 0

Answer:

B. x    

Step-by-step explanation:  

We are asked to choose the correct option that represents the verbal expression: all real numbers less than 70.    

First of all we will see the meaning of inequality signs.

a\leq b This sign means a is less than or equal to b.  

a This sign means a is less than b.

a>b This sign means a is greater than b.

a\geq b This sign means a is greater than or equal to b.    

Now let us represent our given verbal expression in an inequality.

x

Upon looking at our given choices we can see that option B is the correct choice.

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Trisha borrowed money from her mom to buy a skateboard plus safety gear. She paid back a little bit of money every week.
Andrei [34K]

Answer:

y==$281+$166=$447

in 11 weeks she pay $ 447

in 1 weeks she pay $447/11=40.6$

she paid off in 3+8=11 weeks

I am not sure

7 0
3 years ago
Read 2 more answers
What is the volume of a hemisphere with a radius of 3.8in, rounded to the nearest tenth of a cubic inch
Pavel [41]

Answer: 114.9\ in.^3

Step-by-step explanation:

Given

The radius of the hemisphere is r=3.8\ in.

The volume of a hemisphere is given by

V=\dfrac{2}{3}\pi r^3

Insert the value

V=\dfrac{2}{3}\pi \times (3.8)^3\\\\V=114.9\ in.^3

7 0
3 years ago
An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth
sattari [20]
They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east.  Then we can say that there positions, y and x are:

y=150-600t  x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)


7 0
3 years ago
1/2 Divided by 3/4 = explain
xeze [42]

\huge{\green {\sf \underline{Answer:}}}

______________________________________

Step 1:

\frac{1}{2}  \div  \frac{3}{4}

Write the equation

______________________________________

step 2:

\frac{1}{2}  \times  \frac{4}{3}

due to reciprocal 4 comes up and 3 comes down

______________________________________

step 3:

\frac{2}{3}

divide 4 with 2

______________________________________

step 4:

0.667

finally we get 0.667

______________________________________

⚡final answer:

0.667✓

______________________________________

hope it helped you:)

have a nice day!

6 0
3 years ago
Read 2 more answers
Find the area of the triangle whose vertices are (0,4) , (0,0) and (2,0) by plotting them on graph
Luden [163]

Refer to the attached image. Since one vertex is the origin and the other two lay on the coordinate axes, the triangle is a right triangle. This means that, if we consider AB to the be base, AC is his height, and vice versa.

Anyway, it means that the area is given by

A = \cfrac{\overline{AB}\times\overline{AC}}{2}

Since AB is a horizontal segment and AC is a vertical segment, their length is given by the absolute difference of the non-constant coordinate: points A and B share the same x coordinate, so we subtract the y coordinates:

\overline{AB} = |2-0| = |2| = 2

The opposite goes for AC: points A and C share the same y coordinate, so we subtract the x coordinates:

\overline{AC} = |4-0| = |4| = 4

So, the area is

A = \cfrac{2\times 4}{2} = 4

4 0
3 years ago
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