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3 years ago

Number 3 I don’t understand it

Mathematics

1 answer:

yuradex [85]3 years ago

5 0

The measures of complementary angles add up to 90 degrees. Angles A and B therefore add up to 90 degrees.

To find the value of x, set the sum of (the measures of) A and B to 90 (degrees), and solve algebraically.

m∠A + m∠B = 90°
(3x + 5)° + (2x - 15)° = 90°

5x - 10 = 90
5x = 100

x = 20

Then, plug the value of x back into each expression to find the measures of angles A and B.

m∠A = (3x + 5)°
m∠A = (3(20) + 5)°
m∠A = (60 + 5)°

m∠A = 65°

m∠B = (2x - 15)°
m∠B = (2(20) - 15)°
m∠B = (40 - 15)°

m∠B = 25°

You can check to make sure that the angles are complementary by adding them together. Their measures should equal to 90°.

65° + 25° = 90°

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3 years ago

If ξ={1 , 2 , 3 , . . . , 8 , 9 , 10}

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2 years ago

Read 2 more answers

Someone help me solve

Lady_Fox [76]

First draw sloping up (steep because he’s running)to the right until you hit 20 on the y axis. Next draw down and to the right for 5 yards until 15 on y axis. Next is a flat horizontal line for 3 seconds on x axis. Finally a shallow slope line down (because he is walking) and right until you hit the x axis.

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3 years ago

Find the equation of the line that passes through (0, -3) and is parallel to

Tresset [83]

Hey there!

$\\$

Answer:

$\green{\boxed{\red{\bold{\sf{y = \dfrac{7}{6}x - 3}}}}}$

$\\$

Explanation:

To find the equation of a line, we first have to determine its slope knowing that parallel lines have the same slope.

Let the line that we are trying to determine its equation be $\: \sf{d_1} \:$ and the line that is parallel to $\: \sf{d_1} \:$ be $\: \sf{d_2} \:$ .

$\sf{d_2} \:$ passes through the points (9 , 2) and (3 , -5) which means that we can find its slope using the slope formula:

$\sf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{\green{y_2} - \orange{y_1}}{\red{x_2} - \blue{x_1 }}}$

$\\$

⇒Subtitute the values :

$\sf{(\overbrace{\blue{9}}^{\blue{x_1}}\: , \: \overbrace{\orange{2}}^{\orange{y_1}}) \: \: and \: \: (\overbrace{\red{3}}^{\red{x_2}} \: , \: \overbrace{\green{-5}}^{\green{y_2}} )}$

$\implies \sf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{\green{-5} - \orange{2}}{\red{ \: \: 3} - \blue{9 }} = \dfrac{ - 7}{ - 6} = \boxed{ \bold{\dfrac{7}{6} }}}$

$\sf{\bold{The \: slope \: of \: both \: lines \: is \: \dfrac{7}{6}}}$ .

Assuming that we want to get the equation in Slope-Intercept Form, let's substitute m = 7/6:

Slope-Intercept Form:

$\sf{y = mx + b} \\ \sf{Where \: m \: is \: the \: slope \: of \: the \: line \: and \: b \: is \: the \: y-intercept.}$

$\implies \sf{y = \bold{\dfrac{7}{6}}x + b}$ $\\$

We know that the coordinates of the point (0 , -3) verify the equation since it is on the line $\: \sf{d_1} \:$ . Now, replace y with -3 and x with 0:

$\implies \sf{\overbrace{-3}^{y} = \dfrac{7}{8} \times \overbrace{0}^{x} + b} \\ \\ \implies \sf{-3 = 0 + b} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf{\boxed{\bold{b = -3}} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$