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ch4aika [34]
4 years ago
8

1.A 2000 W toaster operates on a household circuit of 200 V. What is the resistance of the wire the make up the heating element

of the toaster?
2.An electronic device is rated at 0.35 W when connected to 150 V. What is the resistance of this device?
Mathematics
1 answer:
MakcuM [25]4 years ago
4 0
P - power measured in watts
E - voltage measured in volts
I - current measured in amperes
R - resistance measured in ohms

E=IR
\\P=IE

1. P = 2000 W, E = 200 V, R = ?

P=IE
\\2000=I200 
\\I=10
\\E=IR
\\200=10R
\\R=20

2. P = 0.35 W, E = 150 V, R = ?

P=IE
\\0.35=I150
\\I= \frac{0.35}{150}
\\ E=IR
\\150=\frac{0.35}{150}R
\\R= \frac{150^2}{0.35}
\\R= 64285.71

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butalik [34]

**Hope This Helps**

Exact Form:

-41/4

Decimal Form:

-10.25

Mixed Number Form:

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3 0
3 years ago
Well I'm having troubles with something I have no idea what it is or how to do it. The problem is x^2 -18x+8=0. I only know how
Lubov Fominskaja [6]

Answer:

x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}

x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}

Step-by-step explanation:

We have the following equation:

x^2 -18 x +8 =0

We can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where:

a = 1 , b=-18, c =8

And replacing we got:

x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}

x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}

6 0
3 years ago
Elaine has a piece of wire that is 2.16 m long. John has a piece of wire that is 2.061 m long. Who is piece of wire is longer? H
lesya [120]
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4 0
4 years ago
15. Before oil is added to a certain road surface material, the other ingredients are mixed. The mixture contains
mojhsa [17]

Answer:

sand = 3450 pounds

3/4 inch stones =6750 pounds

1 inch stones =4800 pounds.

Step-by-step explanation:

The mixture composition is :

45% three-quarter inch stones

32% inch stones and

sand for balance

The percent here is by mass of material used.

Weight of mixture is 15,000 pounds before oil addition.

Use the percent by weight for the two types of stones and calculate real values in pounds

Formula to apply is:

Mass percent = (mass of a material/ total mass of mixture) * 100

For 3/4 inch stones it will be:

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The 3/4 inch stones weigh 6750 pounds

The 1 inch stones will be

32/100 * 15000 =4800

The 1 inch stones weigh = 4800 pounds

Total for the two items : 4800+6750 =11550 pounds

The sand used weighs : 15000 - 11550 = 3450 pounds

8 0
4 years ago
Simplify . 7+ the square root of 6(3+4)-2+9-3*2^2 The solution is
Sonbull [250]

Answer:

7+sqrt(37)

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6 0
3 years ago
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