Question

Well I'm having troubles with something I have no idea what it is or how to do it. The problem is x^2 -18x+8=0. I only know how to set it up. I know that you group the x^2=0 and -18x+8=0

Answer 1

Answer:

$x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}$

$x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}$

Step-by-step explanation:

We have the following equation:

$x^2 -18 x +8 =0$

We can use the quadratic formula given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where:

$a = 1 , b=-18, c =8$

And replacing we got:

$x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}$

$x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}$