Question

A dealer dealt the following cards from a shuffled deck: 3 , 2 , 2 , A , K , Q , K , 5 , 2 , 6 4 , 5 , K , 2 , 7 , 6 , A , J , J , A What was the experimental probability of dealing a black card?

Answer 1

Answer:

Total number of cards in shuffled deck=3 , 2 , 2 , A , K , Q , K , 5 , 2 , 6, 4 , 5 , K , 2 , 7 , 6 , A , J , J , A .

Total number of cards in a deck of card = 52 cards, out of which 26 are black cards and 26 are red card.

As, it is not given that out of the 20 cards dealt by dealer is either red card or black card.

A=3=2B +1 R or 1 B + 2 R

2=4=2 R +2 B

3=1=1 R or 1 B

4=1=1R or 1 B

5=2=2 R or 2 B

6=2=2 R or 2 B

7=1=1 R or 1 B

8=0

9=0

10=0

J=2= 2 R or 2 B

K=3= 2 R + 1 B or 1 R +2 B

Q=1=1 R or 1 B

If you count total number of black cards among the number of cards dealt by dealer, the possibilities of black card drawn is either 15 or 16 from 20 cards drawn.

As, Experimental probability is the probability obtained through experiment which is different from theoretical Probability.

Total number of cards =52

So, Probability of dealing with black cards by dealer which is either 15 or 16 in number is given by

$=\frac{\text{total favorable outcome}}{\text{total possible outcome}}\\\\\frac{15}{52} {\text{or}} \frac{16}{52}=\frac{4}{13}.$

Answer 2

Answer:

40%

Step-by-step explanation:

There are 20 cards in total.

8 are black: 3,2,K,5,6,4,A,J

12 are red: 2,A,K,Q,2,5,K,2,7,6,J,A

so that means 8 of the 20 are black or 8/20

and 8/20 is 40% which is your answer.