Let , side lawn is a.
Area of boundary is :

Now, total cost is given by :

Area left is :

Price to empty space with turfs is :

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.
Answer:
I'm not sure
Step-by-step explanation:
I don't even think that is possible
Answer:
Step-by-step explanation:
soorry can see the pic
Answer:
21
Step-by-step explanation:
literally says it in the text ight
Step-by-step explanation:
G(x) = - x^2 + 10x
a + G(a) = a - a^2 + 10a = - a^2 + 11a or 11a - a^2 or a(11 - a)
1/G(a) = 1/(10a - a^2) = 1/a(10 - a)