The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
brainly.com/question/4785696
#SPJ1
Answer:
[-20.25;+∞).
Step-by-step explanation:
1) according to the properties of the given parabola the minimum is:
2) y₀=-20.25 means, the value -20.25 is minimum of the range, the maximum →+∞;
3) finally, the range y≥-20.25.
Answer:
76.8
Step-by-step explanation:
Using the proportion
→ Percent is out of 100
= 
( cross- multiply )
100n = 7680 ( divide both sides by 100 )
n = 76.8
To solve this equation simply find 2 numbers that multiply to give -4 and add also to give 3, these numbers are 4 and -1. Since 4 • -1 = -4 and 4 + -1 = 3.
X^2 + 3x - 4 = 0
(X - 1)(X + 4) = 0
X = -4 and X = 1 in ascending order.
2 students more were introducced in the class and each group had 8 people
