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quester [9]
2 years ago
9

ABCD is an isosceles trapezoid.

Mathematics
2 answers:
timurjin [86]2 years ago
7 0

Answer:

127

Step-by-step explanation:

Eduardwww [97]2 years ago
6 0

Answer:

∡b = 53°

∡d = 127°

∡c = 127°

Step-by-step explanation:

in trapezoids, the two top angles are equal and the two bottom are equal

also, there are 360 degrees in any 4-sided polygon

53 + 53 + x + x = 360

2x + 106 = 360

2x = 254

x = 127

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21 m<br> 17 m<br> Find the area
Burka [1]

Answer:

357

Step-by-step explanation:

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3 years ago
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If the diameter is 21m what is the radius?<br><br> if the radius is 3.25mm what is diameter?
RoseWind [281]

Answer:

(a)

radius=diameter/2

=21/2=10.5m

(b)

radius=diameter/2

=3.25/2=1.625mm

I would appreciate if my answer is chosen as a brainliest answer

3 0
3 years ago
Can someone solve this, you don’t have to type an explanation, thank you.
iogann1982 [59]

Answer:

70

Step-by-step explanation:

3 0
3 years ago
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Ms. Reynold's sprinkler system has 5 stations that water all parts of her front and back lawn. Each station runs for an equal am
mina [271]

Answer: 40 minutes

Step-by-step explanation:

It takes 16 minutes for the first 2 stations to water their sections which means that the time taken per station is:

= 16/2

= 8 minutes per station

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= 8 * 5

= 40 minutes

3 0
2 years ago
Find the sum or difference. a. -121 2 + 41 2 b. -0.35 - (-0.25)
s344n2d4d5 [400]

Answer:

2

Step-by-step explanation:

The reason an infinite sum like 1 + 1/2 + 1/4 + · · · can have a definite value is that one is really looking at the sequence of numbers

1

1 + 1/2 = 3/2

1 + 1/2 + 1/4 = 7/4

1 + 1/2 + 1/4 + 1/8 = 15/8

etc.,

and this sequence of numbers (1, 3/2, 7/4, 15/8, . . . ) is converging to a limit. It is this limit which we call the "value" of the infinite sum.

How do we find this value?

If we assume it exists and just want to find what it is, let's call it S. Now

S = 1 + 1/2 + 1/4 + 1/8 + · · ·

so, if we multiply it by 1/2, we get

(1/2) S = 1/2 + 1/4 + 1/8 + 1/16 + · · ·

Now, if we subtract the second equation from the first, the 1/2, 1/4, 1/8, etc. all cancel, and we get S - (1/2)S = 1 which means S/2 = 1 and so S = 2.

This same technique can be used to find the sum of any "geometric series", that it, a series where each term is some number r times the previous term. If the first term is a, then the series is

S = a + a r + a r^2 + a r^3 + · · ·

so, multiplying both sides by r,

r S = a r + a r^2 + a r^3 + a r^4 + · · ·

and, subtracting the second equation from the first, you get S - r S = a which you can solve to get S = a/(1-r). Your example was the case a = 1, r = 1/2.

In using this technique, we have assumed that the infinite sum exists, then found the value. But we can also use it to tell whether the sum exists or not: if you look at the finite sum

S = a + a r + a r^2 + a r^3 + · · · + a r^n

then multiply by r to get

rS = a r + a r^2 + a r^3 + a r^4 + · · · + a r^(n+1)

and subtract the second from the first, the terms a r, a r^2, . . . , a r^n all cancel and you are left with S - r S = a - a r^(n+1), so

(IMAGE)

As long as |r| < 1, the term r^(n+1) will go to zero as n goes to infinity, so the finite sum S will approach a / (1-r) as n goes to infinity. Thus the value of the infinite sum is a / (1-r), and this also proves that the infinite sum exists, as long as |r| < 1.

In your example, the finite sums were

1 = 2 - 1/1

3/2 = 2 - 1/2

7/4 = 2 - 1/4

15/8 = 2 - 1/8

and so on; the nth finite sum is 2 - 1/2^n. This converges to 2 as n goes to infinity, so 2 is the value of the infinite sum.

8 0
3 years ago
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