Answer:
The required equation of line in point-slope form is:
Step-by-step explanation:
Given points are:
(x1,y1) = (3,6)
(x2,y2) = (5,-8)
The point-slope form of an equation is given by:
Here m is slope of the line and (x1,y1) is a point on line
The slope is calculated using the formula:
Putting the values we get
Putting in the equation
Now we have to put a point in the equation, putting (3,6) in the equation
Hence,
The required equation of line in point-slope form is:
Answer:
70
Step-by-step explanation:
Evaluate 3 b^2 - b where b = 5:
3 b^2 - b = 3×5^2 - 5
Hint: | Evaluate 5^2.
5^2 = 25:
3×25 - 5
Hint: | Multiply 3 and 25 together.
3×25 = 75:
75 - 5
Hint: | Subtract 5 from 75.
| 7 | 5
- | | 5
| 7 | 0:
Answer: 70
Y+2=-4x+24
2=-4x-y+24
-22=-4x-y
We subtract 32 and 24 from 1219 and we get the answer. 1219-32-24=1163. 1,163 books were left.
1: always rearrange the equation to y = mx + c so....
x - y = o
x = y
So the gradient is 1 and it intersects the y axis at (0,0)
The three points could be (1,1), (2,2), (3,3) and so on
2: -x -2y = -10
Multiply everything by -1
x + 2y = 10
2y = 10 - x
y = 5 - x/2
The y intercept is 5 so you could use the point (0,5), (2,4), (4,3) and so on
3: x + y = -2
y = -2 - x
The y intercept is -2 so you could use the points (0,-2), (2,-4), (3,-5) and so on
4: -3y =-x -7
Multiply everything by -1
3y = x + 7
y = x/3 + 7/3
The y intercept is 7/3 so you could use the points (0,7/3), (3,10/3), (6,13/3) and so o
5: -y = -x + 1
y = x - 1
The y intercept is -1 so you could use the points (0,-1), (2,1), (3,2) and so on
Hope this helps! Any questions let me know :)
