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Ierofanga [76]
3 years ago
14

Using the segment addition postulate, which is true?

Mathematics
2 answers:
gulaghasi [49]3 years ago
7 0
The answer is BC + CD = BD
Reika [66]3 years ago
5 0

Answer: The answer is (d) BC + CD = BD.

Step-by-step explanation:  We are given the number line and four points A, B, C and D on the line with co-ordinate -6, -1, 2 and 8 respectively.

We are to select the correct statement out of the given four.

(a) L.H.S. = AB + BC = 5 + 3 = 8,

    R.H.S = AD = 14 ≠ 8.

So, this option is incorrect.

(b) L.H.S. = AB + BC = 5 + 3 = 8,

    R.H.S = CD = 6 ≠ 8.

So, this option is incorrect.

(c) L.H.S. = BC + CD = 3 + 6 = 9,

    R.H.S = AD = 14 ≠ 9.

So, this option is incorrect.

(d) L.H.S. = BC + CD = 3 + 6 = 9,

    R.H.S = BD = 9.

So, this option is correct.

Thus, the correct option is (d).

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In parallelogram abcd, ab=14, bc=20, m(angle)b=54. Find to the nearest tenth the length of diagonal bd, and find measure angle d
muminat
It is is a parallelogram, hence we have to face sides equal in length and the opposite angles are also the same. From the given above we have:
ab=14 and its opposite side cd=14
bc=20 and its opposite side da=20

Solving for the diagonal measurement bd, we have consecutive angles are equal to 180°
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∠A=126° , ∠B=54° ,∠C=126° and ∠D=54°
bd²=ab²+da²-2(ab)(da)cos126°
bd²=14²+20²-2*14*20cos126°
bd=30.42 unit

Solving for the angle dbc, we have
cos dbc=bc²+bd²-cd²/a*bc*bd
cos dbc=20²+30.42²-14²/2*20*30.42
dbc=21.76° 
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