The answer is i don’t know but am answering this for points ):
Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°
2x-2 must be zero or greater, since we cannot have a negative quantity under the radical sign (unless we allow for imaginary roots).
Solving 2x-2≥0, we get x-1≥0, or x≥1. x must be equal to or greater than 1.
16 - 16, so the answer to the 2nd problem is the fourth one: x=4.
The answer to this question is 6 in. Hope this helps.
Answer:
Not me
Step-by-step explanation:
im in high school lol
