PLEASE HELP!

1 answer:

6 0

Complete the square
(h,k) is the vertex

so
f(x)=2x²-12x+16
group x terms
f(x)=(2x²-12x)+16
factor out the 2
f(x)=2(x²-6x)+16
take 1/2 of the linear coefient and square it
-6/2=-3, (-3)²=9
add positive and negative insides parnthases
f(x)=2(x²-6x+9-9)+16
factor perfect square
f(x)=2((x-3)²-9)+16
distribute
f(x)=2(x-3)²-18+16
f(x)=2(x-3)²-2

h=3
k=-2
vertex is (3,-2)
vertex form is f(x)=2(x-3)²-2

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To solve this problem you must apply the proccedure shown below:
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$