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Sidana [21]
3 years ago
8

Which of the following equations represents a nonlinear function?

Mathematics
1 answer:
Ainat [17]3 years ago
8 0
Y=square root of x

All the others would be a straight line with an unchanging slope (meaning they're linear). Y=rootx is not linear.
I hope this Helps!
You might be interested in
Solve the system by the substitution method.
Ghella [55]

Answer:

A) The solution set is (6,-8).

Step-by-step explanation:

3x - y = 26

-3x       - 3x        Subtract 3x from both sides

-y = -3x + 26     Divide both sides by -1

y = 3x - 26

Now plug this into 7x + 8y = -22 to solve for x

7x + 8(3x - 26) = -22        Distribute

7x + 24x - 208 = -22       Combine like terms

31x - 208 = -22

     + 208    + 208            Add 208 to both sides

31x = 186                           Divide both sides by 31

x  = 6

Plug this into y = 3x - 26 to solve for y

y = 3(6) - 26           Multiply

y = 18 - 26              Subtract

y = -8

If this answer is correct, please make me Brainliest!

8 0
3 years ago
2/7m-1/7=3/14 solve step by step
yulyashka [42]

Solution for \frac{2}{7}m - \frac{1}{7} = \frac{3}{14} \ is \ m = \frac{5}{4} \ or \ m = 1\frac{1}{4} \ or \ m = 1.25

<h3>Further explanation</h3>

It is a case about one variable linear quations and we have to solve the equation to get the variable m. There are two ways to solve it!

Our main plan is to isolate the variable m alone at the end of the process on one side of the equation until the variable will be equal to the value on the opposite side.

<u>First way</u>

\frac{2}{7}m - \frac{1}{7} = \frac{3}{14}

Let us add \frac{1}{7} to both sides

\frac{2}{7}m - \frac{1}{7} + \frac{1}{7} = \frac{3}{14} + \frac{1}{7}

\frac{2}{7}m = \frac{3}{14} + \frac{1}{7}

On the right side for the addition operation, we equate the common denominator by multiplying \ \frac{1}{7} \ by \ \frac{2}{2}

\frac{2}{7}m = \frac{3}{14} + \frac{2}{14}

Then we combine terms to get

\frac{2}{7}m = \frac{5}{14}

Divide by the coefficient of m, or in other words, multiply both sides by \frac{7}{2}

\frac{2}{7}m \times \frac{7}{2} = \frac{5}{14} \times \frac{7}{2}

Finally, the solution is obtained as follows

m = \frac{35}{28}

Simplify fractions, both the numerator and denominator are divided equally by 7.

\boxed{ \ m = \frac{5}{4} \ }

Convert into mixed fractions, we get:

\boxed{ \ m = 1 \frac{1}{4} \ }

In decimal form, we get

m = 1 \frac{25}{100} \rightarrow \boxed{ \ m = 1.25 \ }

<u>Second way (a quick way)</u>

\frac{2}{7}m - \frac{1}{7} = \frac{3}{14}

Because the denominators 7 and 14 have LCM = 14, both sides are multiplied by 14 (LCM is the Least Common Multiple)

14 \times \big( \frac{2}{7}m - \frac{1}{7} \big) = 14\times \big( \frac{3}{14} \big)

We use the distributive property of multiplication on the left side

\frac{28}{7}m - \frac{14}{7} = \frac{42}{14}

or it can also directly lead to

4m - 2 = 3

Add 2 to both sides, we get

4m = 5

Divide by the coefficient of m, or in other words, both sides are divided by 4

\boxed{ \ m = \frac{5}{4} \ }

Or, \boxed{ \ m = 1 \frac{1}{4} \ }

Or, m = 1 \frac{25}{100} \rightarrow \boxed{ \ m = 1.25 \ }

Wanna check the solution into the equation?

\big( \frac{2}{7} \times \frac{5}{4} \big) - \frac{1}{7} = \frac{3}{14}

\frac{10}{28} - \frac{1}{7} = \frac{3}{14}

\frac{5}{14} - \frac{2}{14} = \frac{3}{14}

\frac{3}{14} = \frac{3}{14}

Both sides show the same value, so the solution is correct.

Note:

Remember, how to manipulate both sides of the equation with the algebraic properties of equality such as:

  • adding,
  • subtracting,
  • multiplying, and/or
  • dividing both sides of the equation with the same number.

In the form of fractions, the steps that must be considered are

  • equate the denominator,
  • simplify fractions, and
  • for the final answer, convert fractions to mixed fractions or decimal forms

All these processes can occur repeatedly until the isolated variables are obtained on one side of the equation.

<h3>Learn more</h3>
  1. A word problem that forms a single variable linear equation brainly.com/question/1566971
  2. Learn more about the single variable linear equation that has no solution, has one solution, and has infinitely many solutions brainly.com/question/2595790  
  3. Questioning the stages of solving a word problem about one variable linear equations brainly.com/question/2038876
<h3>Answer details  </h3>

Grade : Middle School

Subject : Mathematics

Chapter : Linear Equation in One Variable

Keywords : solve, solution, variable, coefficient, 2/7m - 1/7 = 3/14,  5/4, 1 1/4, 1.125, algebraic properties of equality, one, linear equation, isolated, manipulate, operations, add, subtract, multiply, divide, fraction, equate, denominator, numerator, both sides, decimal

4 0
3 years ago
Read 2 more answers
Help me please with 23-26 compare use &lt; &gt; =
Andreyy89
23. =
24. >
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8 0
3 years ago
Read 2 more answers
(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti
Rashid [163]

Answer:

The solution

Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

<em>Step(i)</em>:-

Given differential problem

                           y′+3 y=9 t

<em>Take the Laplace transform of both sides of the differential equation</em>

                L( y′+3 y) = L(9 t)

 <em>Using Formula Transform of derivatives</em>

<em>                 L(y¹(t)) = s y⁻(s)-y(0)</em>

  <em>  By using Laplace transform formula</em>

<em>               </em>L(t) = \frac{1}{S^{2} }<em> </em>

<em>Step(ii):-</em>

Given

             L( y′(t)) + 3 L (y(t)) = 9 L( t)

            s y^{-} (s) - y(0) +  3y^{-}(s) = \frac{9}{s^{2} }

            s y^{-} (s) - 7 +  3y^{-}(s) = \frac{9}{s^{2} }

Taking common y⁻(s) and simplification, we get

             ( s +  3)y^{-}(s) = \frac{9}{s^{2} }+7

             y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}

<em>Step(iii</em>):-

<em>By using partial fractions , we get</em>

\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}

  \frac{9}{s^{2} (s+3} =  \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}

 On simplification we get

  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

 Put s =0 in equation(i)

   9 = B(0+3)

 <em>  B = 9/3 = 3</em>

  Put s = -3 in equation(i)

  9 = C(-3)²

  <em>C = 1</em>

 Given Equation  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

  9 = A s²+3 A s +B(s)+3 B +C(s²)

 <em> 0 = A + C</em>

<em>put C=1 , becomes A = -1</em>

\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}

<u><em>Step(iv):-</em></u>

y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}

y^{-}(s)  =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}

Applying inverse Laplace transform on both sides

L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})

<em>By using inverse Laplace transform</em>

<em></em>L^{-1} (\frac{1}{s} ) =1<em></em>

L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}

L^{-1} (\frac{1}{s+a} ) =e^{-at}

<u><em>Final answer</em></u>:-

<em>Now the solution , we get</em>

Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}

           

           

5 0
2 years ago
The midpoint between (–4, 8) and (0, 10) is (x, y). What is x?
Dmitrij [34]

Answer:

x = -2

Step-by-step explanation:

The x coordinate of the midpoint is found by adding the x coordinates together and dividing by 2

( -4+0)/2 = -4/2 = -2

The y coordinate of the midpoint is found by adding the y coordinates together and dividing by 2

( 8+10)/2 = 18/2 = 9

7 0
3 years ago
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