The amount for the investment of $6000 will be a.$6369 b. $6090 and c.$6030.
<h3>What is compound interest?</h3>
Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-
![A=P[1+\dfrac{r}{n}]^{nt}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7Bn%7D%5D%5E%7Bnt%7D)
a) The amount in the bank after 6 years if interest is compounded annually.
![A=P[1+\dfrac{r}{1}]^{t}\\\\\\A=6000[1+\dfrac{0.01}{1}]^{ 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B1%7D%5D%5E%7Bt%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B1%7D%5D%5E%7B%20%206%7D)
A= $6369
b) The amount in the bank after 6 years if interest is compounded quarterly.
![A=P[1+\dfrac{r}{4}]^{4t}\\\\\\A=6000[1+\dfrac{0.01}{4}]^{4\times 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B4%7D%5D%5E%7B4t%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B4%7D%5D%5E%7B4%5Ctimes%206%7D)
A= $6090
c ) The amount in the bank after 6 years if interest is compounded monthly.
![A=P[1+\dfrac{r}{12}]^{4t}\\\\\\A=6000[1+\dfrac{0.01}{12}]^{12\times 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B12%7D%5D%5E%7B4t%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B12%7D%5D%5E%7B12%5Ctimes%206%7D)
A=$6030
Hence the amount for the investment of $6000 will be a.$6369 b. $6090 and c.$6030.
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Hope this helps with your question;)
Any line can be expresses as:
y=mx+b where m=slope=(y2-y1)/(x2-x1) and b=y-intercept (value of y when x=0)
First find the slope:
m=(2-0)/(8-0)=2/8=1/4 so we have thus far:
y=0.25x+b, we solve for b using any point on the line, (8,2)
2=0.25(8)+b
2=2+b
0=b
So the line is:
y=.25x which they might also express as y=x/4
The answer is E. (1/4)x
Answer:
C
Step-by-step explanation:
Because u need to find the LCD and the LCD of 4 and 7 is 28