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stira [4]
4 years ago
15

What is the product? (7x2y3)(3x5y8)

Mathematics
2 answers:
frutty [35]4 years ago
6 0

Answer:

Product (21) ( x^{7})(y^{11}).

Step-by-step explanation:

Given : (7x^{2} y^{3})(3x^{5} y^{8}).

To find : product .

Solution : We have given that

(7x^{2} y^{3})(3x^{5} y^{8}).

Combine like terms

(7 * 3) ( x^{2}*x^{5})(y^{3}*y^{8}).

By the exponential rule : if the base of two exponent is same then power must be added . x^{a} *x^{b} = x^{a+b}.

Then

(21) ( x^{2+5})(y^{3+8}).

(21) ( x^{7})(y^{11}).

Therefore, Product (21) ( x^{7})(y^{11}).

natima [27]4 years ago
4 0

i don't know if this is the correct answer 3360y^2

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I dont understand pls help plsssssssss
Kipish [7]

Answer:

m∠CBD=68

Step-by-step explanation:

BA ⊥ BD

m∠ABD=90°

So  m∠CBD+m∠ABC=90

(4x+52)+(8x-10)=90

12x=48

   x=4

m∠CBD= 4(4)+52

             =<u>68 </u>

<u>hope this helps</u>

4 0
3 years ago
Please Help! If (3x+5)^2=ax^2+bx+c, what is the value of a+b+c?
Alisiya [41]

Answer:

64

Step-by-step explanation:

You open up the (3x+5)^2 and get:

9x^2 + 30x + 25

So...

a+b+c = 64

OR

You add the coefficient(s) and the constant together in the parentheses and get:

(3x+5)^2 --> (8)^2

So you square the 8 and get:

64

4 0
4 years ago
Write the equation of the circle centered at (-4,6) with a diameter of 16
steposvetlana [31]
<span>Center:(-4,6)
The center of a circle is a point from which all points on a circle are the same distance.Radius:8
The radius of a circle is the length of a line segment from its center to its perimeter.
The radius is typically denoted as "r" or "R".Diameter:16
The diameter of a circle is any straight line segment that passes through the center of the circle and whose endpoints lie on the circle. It can also be defined as the longest chord of the circle.Circumference or (or Permieter) = 2*π*R = 2*3.14*8 = 50.2654824574367
The circumference of a circle is the distance around it.Area:201.061929829747
Area of a Circle is the amount of space occupied by the circle.The area of a circle is p times the radius squared, which is written: A = π*R2.</span>EquationStandard Form

The standard form for the equation oif a circle is
(x-a)2+(y-b)2=r2
And in our particular case:
(x--4)2+(y-6)2=82
(x+4)2+(y-6)2=82
(x+4)2+(y-6)2=64

General Form

The general form for the equation of a circle is
x2 + y2 + Ax + By + c = 0
We can get the general form by expanding the equation of the standard form
(x-a)2+(y-b)2=r2
(x--4)2+(y-6)2=82
(x+4)2+(y-6)2=64
x2+8x+16+y2-12y+36=64
x2+y2+8x-12y-12=0


6 0
3 years ago
PLEASE HELP MY ASSIGNMENT IS DUE IN LESS THAN A HOUR!!!!
Leno4ka [110]

Answer:

77 degrees c:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can anyone please help i am stuck on this question?
ale4655 [162]

Answer:

8/17

General Formulas and Concepts:

<u>Trigonometry</u>

  • [Right Triangles Only] cos∅ = adjacent over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a right triangle. We can use trig to find the ratio.

<u>Step 2: Identify</u>

<em>POV from angle S</em>

Adjacent = 8

Hypotenuse = 17

<u>Step 3: Write</u>

  1. Substitute [cosine]:                    cos(s) = 8/17
5 0
3 years ago
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