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Anton [14]
4 years ago
8

Segment VU is 2 units and segment VꞌUꞌ is 4units.

Mathematics
1 answer:
kicyunya [14]4 years ago
4 0
In the figure the segment both VU and V'U' are horizontal, so the segment VU was scaled by a factor of 2 to dilate it and get the segment V'U'.

You can check that the same factor was used for all the segments to obtain a similar figure.
You might be interested in
If a roasting is 600mm x 500mm how many 25cm cake time will fit on it?
nydimaria [60]
So assuming that 25cm is 25 square cm because you cannot have a 2 dimentional cake so

600mm by 500mm
to find the area, multiply legnth by width

mm=milimeters
cm=centimeters
this is in mm so
1cm=10mm
1mm=1/10cm
to convert from mm to cm, you divide by 10
we must divide by 10 first
legnth =600mm
600/10=60cm
legnth=60cm

width=500mm
500/10=50cm
width=50cm

area=60 times 50=3000 square cm or cm^2
so 3000 is the area
25 is the area of each cake
divide 3000 into 25 and find how many cakes will fit

3000/25=120

120 cakes will fit

3 0
3 years ago
What is the first step needed to solve 3 over 4 multiplied by x minus 3 equals negative 18?
kodGreya [7K]
Minus 3 from the 3 and the 18
7 0
3 years ago
Help with the CORRECT answer pretty please
lilavasa [31]
The answer would be (3,-1)
7 0
3 years ago
Read 2 more answers
If f(x) = 3LX-2], what is f(5.9)? 9 10 11 12​
Black_prince [1.1K]

Answer: 12

Step-by-step explanation:

We know that , the ceiling function y = [x] is also known as the least integer function that gives the smallest integer greater than or equal to x.

For example : For x= 1.5

y = [1.5] =2

For x= 3.64

y = ⌊3.64⌋=4

The given function :

Then, for x= 5.9 , we have

[since [3.9]=4 (least integer function)]

Therefore, the value of f(5.9) is 12

6 0
3 years ago
Read 2 more answers
3. If 3, x, y, 18, are in arithmetic progression, (A, P) find the value of x and y
Luba_88 [7]

Answer:

Below in bold

Step-by-step explanation:

The sequence is:

3, x, y, 18

If this is an A P then

x - 3 = y - x  

2x - y = 3      (A)  and

y - x = 18 - y

2y - x = 18      (B)

Multiply  (A) by 2:

4x - 2y = 6    (C)

Adding B and C:

3x = 24

x = 8.

and

2y - 8 = 18

2y = 26

y = 13.

So x = 8 and y = 13.

b)   ar + ar^2 = 6ar^3  where a = first term and r = common ratio

Divide by a:

r + r^2 = 6r^3

6r^3 - r^2 - r = 0

r(6r^2 - r - 1) = 0

r(3r  + 1)(2r  - 1) = 0

So the 2 possible values of r

= -1/3 and 1/2.

i) The common ratio is positive so it must be 1/2.

Second term ar = 8

1/2 a = 8

a = 16.

So the first 6 terms are:

16, 8, 4, 2, 1, 1/2.

5 0
2 years ago
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